To check if two words are equal to each other?(C)

Question

Hello.I want to make a simple English-Turkish dictionary. This is my homework.I have to code with C but I don't know C at all. Why doesn't my following code work?

#include<stdio.h>
int main()
{
    int i;

    char word_array[10][20] ={"araba","car","kalem","pencil","derin","deep","mavi","blue","el","hand" };
    //char arama[5] = {'d','e','r','i','n'};
    char search[10] = "araba ";


    for(i = 0 ; i < 10; i=i+2){
        if(word_array[i] == search){
            printf("i found: %s\n",i);
        }
        else{
            printf("The word isnt in the array. %s\n",word_array[i],search);
        }
    }

    return 0;
}

no it doesn't. Use `strcmp`. and it won't either because there's a space in the end of `"araba "` — Jean-François Fabre, Nov 22 '16 at 22:24
In C you can neither assign (apart from definitions) or compare a string without using `strcpy` or `strcmp` — Weather Vane, Nov 22 '16 at 22:24
that's right. you cannot compare with "if(word_array[i] == search". try a different data structure and use the string compares as others have said. — john elemans, Nov 22 '16 at 22:25
There's quite a bit wrong with your code example, to the point where someone might need to rewrite the entire block to give you any real help. — Geoherna, Nov 22 '16 at 22:26
@WeatherVane Turkish(even position)-English(odd position) dictionary — BLUEPIXY, Nov 22 '16 at 22:40

score 0 · Accepted Answer · answered Nov 22 '16 at 22:35

0

Review the code below. It fixed few issues with your code.

    #include<stdio.h>
    #include <string.h>
    int main()
    {
        int i;

        char word_array[10][20] ={"araba","car","kalem","pencil","derin","deep","mavi","blue","el","hand" };
        char search[10] = "araba";


        for(i = 0 ; i < 10; i++){
            if(strcmp(word_array[i],search) == 0){
                printf("i found: %s\n",i);
                break;
            }
       }

       if(i>=10) {
            printf("The word %s isnt in the array.\n",search);
        }

        return 0;
    }

answered Nov 22 '16 at 22:35

Yoram

572
6
21

`printf("i found: %d\n",i);` (or `printf("i found: %s\n", word_array[i]);` or `printf("i found: %s\n", word_array[i+1]);`) – BLUEPIXY Nov 22 '16 at 22:45
Thanks for the answer. It's work :) – Enes Körhan Nov 23 '16 at 08:28

score 0 · Answer 2 · edited May 23 '17 at 12:13

0

#include<stdio.h>
#include <string.h> // <-------- Include header containing strcmp()
int main()
{
    int i;

    char word_array[10][20] = { "araba", "car", "kalem", "pencil", "derin", "deep", "mavi", "blue", "el", "hand" };
    //char arama[5] = {'d','e','r','i','n'};
    char search[10] = "araba"; // <-------- Remove space to have the same string.


    for (i = 0; i < 10; i = i + 1){ // <-------- Search each word in array as opposed to each second word.
        if (strcmp(word_array[i], search) == 0){ // <-------- Use proper C-string comparison.
            printf("%i found: %s\n", i, word_array[i]); // <-------- Correct specifier "i" to "%i" and add the actual found word to output for "%s"
        }
        else{
            printf("The word isnt in the array. %s\n", word_array[i], search);
        }
    }

    return 0;
}

Also see: How do I properly compare strings?

edited May 23 '17 at 12:13

Community

1
1

answered Nov 22 '16 at 22:36

BUCH

103
4

`printf("The word isnt in the array. %s\n", word_array[i], search);` : arguments mismatch. and move to outside of for-loop. – BLUEPIXY Nov 22 '16 at 22:48
@BLUEPIXY Depends on what he wants to do with that line(isn't the prettiest that's for sure). However, moving it outside of the loop in it's current form won't do any good. – BUCH Nov 22 '16 at 22:56
Thanks for the answer :) – Enes Körhan Nov 23 '16 at 08:28

To check if two words are equal to each other?(C)

2 Answers2