mockito testing verify with 0 calls

Question

    Class MyClass{
    method3(){
      if(condition){
        method1()
      }

      else{

      method2()

      }

    }

     method1(){
     //do woo
      }

     method3(){
        //do foo
      }
 }

I am trying to test method3 only if case is called so else method is not called.

   MyClass myClassMock=   mock(MyClass.class);
         myClassMock.method3();
         verify( myClassMock, times(0)).method2();

But then this calls my method2 and throws null pointer inside method2. How can I test this without calling method2 because my behavior wont call method2.

Once I fixed the compilation problems this test snippet worked just fine for me. Could you include a [mcve]? — Mureinik, Nov 23 '16 at 19:15

xenteros · Answer 1 · 2016-11-23T19:27:20.567

1

If you don't care what was returned from method2 you can mock the method as well:

when(mock.method2(anyString())).thenAnswer("anything");

You can replace anyString and use the following:

when(mock.method2(any(MyClass.class))).thenReturn(anInstanceOfMyClass);

or

verify(mock, never()).method2();

or

when(mock.method2()).thenReturn(instanceOfProperClass);

edited Nov 23 '16 at 19:27

answered Nov 23 '16 at 19:11

xenteros

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But then this calls method2() .I dont want method 2 be called.inside method 2 I am calling 3 rd party interfaces and call goes there and fails with null pointer. – javascriptlearner Nov 23 '16 at 19:24
Does it take any parameters? Use one of two first approaches. – xenteros Nov 23 '16 at 19:25
Thanks will try it – javascriptlearner Nov 23 '16 at 19:29

mockito testing verify with 0 calls

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