shell script to resume stopped processes

Question

I wrote a shell script to resume all suspended processes. After a research on the commands, this is what I have by now:

#!/bin/bash
for i in `jobs -sp`; do
  kill -CONT $i
done

But nothing seems to happend... I created a dummy shell script that loops forever, runned and stopped it. And after runned my shell script it won't resume. Why is this happening?

Are they waiting for the standard input? Why are they suspended? Run `jobs -l`. — Jdamian, Nov 24 '16 at 16:09
This dummy program is suspended because i called kill -STOP. Edited my question to include this. — S.H., Nov 24 '16 at 16:21

score 0 · Answer 1 · edited May 23 '17 at 11:59

0

You need to use set -m to use job control in a shell script, See Why can't I use job control in a bash script?

Here is my solution:

set -m

while read i
do
  kill -CONT $i
done < <(jobs -sp)

I am using process substitution instead of backticks.

edited May 23 '17 at 11:59

Community

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answered Nov 24 '16 at 19:56

cdarke

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So there is no way doing it in a script? Because I tried your solution on a script and it did not work. – S.H. Nov 24 '16 at 23:50
Did you do the `set -m` in the script? – cdarke Nov 25 '16 at 07:41
OK. Run the script with `xttrace` on (`bash -x script-name`). – cdarke Nov 27 '16 at 08:13

score 0 · Answer 2 · answered Nov 25 '16 at 06:53

Running a script starts a subshell which obviously does not have any stopped jobs because you just started it.

Try putting your code in a function instead, and run it in the shell where you are looking to continue those jobs.

cont () {
    local i
    for i in $(jobs -sp); do
      kill -CONT $i
    done
}

(Notice the preference for $(...) over `...` -- it doesn't make a lot of difference here, but you should learn to prefer the modern syntax for when it does matter.)

The code is so simple that it might not make sense to put it in a function, though. You can simplify further with xargs:

jobs -sp | xargs kill -CONT

shell script to resume stopped processes

2 Answers2