SharpZipLib GetInputStream

Question

I've built a webapplication in which a user can select a zipfile from their filesystem (via an asp:FileUpload). Then the application unzips the zipfile and ftp's every file.

here's the code:

Public Sub Unzip(ByVal str As Stream, ByVal constr As String)
    Dim zf As New ZipFile(str)
    Dim ze As ZipEntry
    Dim i As Integer = 0
    While i < zf.Count
        ze = zf.EntryByIndex(i)
        i = i + 1
        Dim ftp As New ftpItem(constr)
        ftp.upload(ze.Name, "pic", zf.GetInputStream(i), ze.Name, ze.Name)

    End While
    zf.Close() 
End Sub

The ftpItem class is a class of my own which handles the ftp. ftp.upload needs as third parameter the stream for the file to be sent.

But for some reason zf.GetInputStream(i) always gives nothing.

score 0 · Answer 1 · answered Nov 02 '10 at 18:15

0

I think you are at the end of the stream, try moving to the begining of the stream so you can read everything.

str.Seek(0, SeekOrigin.Begin)

answered Nov 02 '10 at 18:15

Chris Kooken

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score 0 · Accepted Answer · edited May 23 '17 at 12:06

0

For one thing, you should increment i inside the loop AFTER you call GetInputStream. If there is only one file this logic will always fail, I imagine.

While i < zf.Count
    ze = zf.EntryByIndex(i)

    Dim ftp As New ftpItem(constr)
    ftp.upload(ze.Name, "pic", zf.GetInputStream(i), ze.Name, ze.Name)

    i = i + 1

End While

If that does not work, there is a purportedly working C# example here, using a different method GetNextEntry to iterate the list of compressed files.

edited May 23 '17 at 12:06

Community

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answered Nov 02 '10 at 18:52

Steve Townsend

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Moving to the begining does not help. still the same result. the increment was indeed in the wrong place. But even placing it right does not help. The entries I get are good, if I run the debugger and I ask ze.Name, it gives me the names of the files; just like ze.Size gives me the right size for the files. (I've also tried iterating like the c# example with no luck) – Ivo Nov 02 '10 at 18:59
@user495089 - is that comment for me, or the answer below? Seems to me like you have a simple logic error here – Steve Townsend Nov 02 '10 at 19:02
Have you tried just writing the uncompressed data to a local file (`FileStream`) or `MemoryStream` instead of using FTP? What do properties look like on `zf.GetInputStream()`? What it the interface to `upload`? Just a `Stream`, or some other class as param 3? – Steve Townsend Nov 02 '10 at 19:20
@Ivo - great, glad to hear it – Steve Townsend Nov 03 '10 at 19:41

SharpZipLib GetInputStream

2 Answers2