Java string tokenizer delimiter

Question

I have a string "domain\cdsid", where "\" is the delimiter, all I want is to split the string and just print "cdsid".

Input string : "domain\cdsid"

Output string : "cdsid"

How do I do this ?

Whay have you tried? Split the string by delimiter and access the resulting array — Andrew Li, Nov 29 '16 at 12:50

score 1 · Answer 1 · answered Nov 29 '16 at 13:08

1

Try this (using split) :

String myText = "domain\\cdsid";
System.out.println(myText.split("\\\\")[1]);

Output :

cdsid

answered Nov 29 '16 at 13:08

Jarvis

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That looks fine, but if you see this here. "String[] loginname= (node.getAttributes().getNamedItem("LoginName").getNodeValue()).split("\\");" Iam extracting the data from sharepoint and its the "LoginName" which has this format "domain\cdsid" its predefined. – Irthiza Khan Nov 29 '16 at 13:12
You can't have a ``\`` inside a String, so, even if the method is returning the string `"domain\cdsid"`, it actually IS `"domain\\cdsid"`, and hence, the corresponding split. – Jarvis Nov 29 '16 at 13:17
Glad you got it. Please mark the answer as accepted. :) @IrthizaKhan – Jarvis Nov 30 '16 at 02:09

SachinSarawgi · Answer 2 · 2016-11-29T13:44:07.370

0

In Java String object "\" is used to define any escape sequence character like \n for new line, \t for tab, \\ for having a backslash in the String object.

So instead of writing String object as

String str = "domain\cdsid";

You have to write

String str = "domain\\cdsid";

The first option will give compile time error. Java will expect that after backslash their must be some escape sequence character but it is not their in first case. It will compile time error as

Invalid escape sequence (valid ones are \b \t \n \f \r \" \' \\ )

In the above compile time error each separate value is a escape sequence character in java.

So your final code will be

String str = "domain\\cdsid";
System.out.println(str.split("\\\\")[1]);

Hope this helps.

edited Nov 29 '16 at 13:44

answered Nov 29 '16 at 13:23

SachinSarawgi

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Do you even ran the code before posting the solution ? – Jarvis Nov 29 '16 at 13:24
Sorry but which part is giving the error ? I already mentioned that first option will give compile time error in the explanation. – SachinSarawgi Nov 29 '16 at 13:34
The `"final"` code you posted. – Jarvis Nov 29 '16 at 13:38
I edited the answer. Thank you Jarvis for letting me know. – SachinSarawgi Nov 29 '16 at 13:39
Understand what you were saying. Edited the answer. – SachinSarawgi Nov 29 '16 at 13:44

score -1 · Answer 3 · answered Nov 29 '16 at 13:23

Splitting is a way that I will recommended to go when you need all the elements resulting of the operation... this is because the result will generate an Array of Strings (what a waste of memory generating an array to only get ONE element! :) dont you think??)

in your case something like regex or just substrings will gently provide you the correct answer..

consider:

String txt = "domain\\cdsid";
System.out.println(txt.substring(txt.indexOf("\\") + 1));

output:

cdsid

Java string tokenizer delimiter

3 Answers3