Loop Removes Zero Before Integer

Question

If my loop runs 3 times, then the output is 0001,2,3, but I need

0001
0002
0003  

How do I get this output?

$i='0001';
foreach($test as $rows){
    echo $i; 
    echo '<br/>';
    $i++;
}

Answer 1

Use printf with a padding specifier, e.g.:

$test = range(1,11);

$i = 0;
foreach ($test as $rows) {
  printf("%04d<br/>\n", ++$i);
}

Output

0001<br/>
0002<br/>
0003<br/>
0004<br/>
0005<br/>
0006<br/>
0007<br/>
0008<br/>
0009<br/>
0010<br/>
0011<br/>

In this example, 04 is a padding specifier meaning that the number (d) is padded with maximum 4 zeroes.

Answer 2

You can use str_pad()

$i = "0001";
for($j=0;$j<1000;$j++) {
  echo str_pad($i++, 4, '0', STR_PAD_LEFT);
  echo "<br/>";
}

Answer 3

You can cheat a little bit,

$i = "1";
$y = "000"; //Added this

while ($i < 4){
    echo $y . $i;
    $i++;
}

Basically you echo the 000 in front of the number each time.