Issues with custom Url Schemes

Question

I have an app lets say 2 apps - app1,app2 Lets say I open from app1 app2. How can I send data back from app2 with custom url schemes,like in facebook app? If I reopen app1 with url,I will see go back to app2,and its not good idea for my case. I want to open app2 like presented modally,and dismiss it with returned data.Is it possible?

Answer 1

You can define custom URL Schema for your app from info.plist file. you can check existing Thread on SO for this.

In your case,for example In app1- define custom url myAppOneScheme and in your app2, Define custom url myAppTwoScheme.

When you open app2 from app 1, Pass app1's url like this:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"myAppOneScheme://test?callerURL= myAppOneScheme"]];

from app2, handle openURL method:

- (BOOL)application:(UIApplication *)application handleOpenURL:(NSURL *)url {
    NSLog(@"url recieved: %@", url);
    NSLog(@"query string: %@", [url query]);
    NSLog(@"host: %@", [url host]);
    NSLog(@"url path: %@", [url path]);
    NSDictionary *dict = [self parseQueryString:[url query]];
    NSLog(@"query dict: %@", dict);
//   NSString callerurl = parse callerURL from query

//  store callerurl in user default or global variable. 
    return YES;
}

when you are done with operations in app2 and want to go back to app1, open caller url

  [[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:"%@//testback?response=%@", caller url , datayouwanttoSendback]]];

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Now, in your app1, again handle open url method and parse response