How to insert char at specific location throughout the string?

Asked Dec 01 '16 at 11:20

Active Dec 01 '16 at 12:50

Viewed 116 times

I want to insert chars at specific location alternatively like :

input : orange

output : or##an##ge##

This is what I've tried:

String output = input.substring(x,x+2) + "00" + input.substring(x+2,x+4) + "00" + input.substring(x+4,x+6) + "00" + input.substring(x+6,7) + "00";

edited Dec 01 '16 at 12:50

ItamarG3

asked Dec 01 '16 at 11:20

HelloWorld

Have you tried coding it? – ItamarG3 Dec 01 '16 at 11:21
Bonus points to anyone who can do this in a single line with `String.replaceAll`. – Tim Biegeleisen Dec 01 '16 at 11:23
@ItamarGreen Yeah I tried using substring ..also got my output..I need to have the same format for any input .... input : programming output : pr##og##ra##mm##in##g## – HelloWorld Dec 01 '16 at 11:27
@Avudai Well... always post what you've tried... – ItamarG3 Dec 01 '16 at 11:28
String output = input.substring(x,x+2) + "00" + input.substring(x+2,x+4) + "00" + input.substring(x+4,x+6) + "00" + input.substring(x+6,7) + "00" ; @ItamarGreen – HelloWorld Dec 01 '16 at 11:31
@Avudai in the question body – ItamarG3 Dec 01 '16 at 11:41
@Tim `System.out.println("orange".replaceAll(".{2}","$0pp"));` Is there a better one? – Curious Dec 01 '16 at 11:53
1

@jay Bummer you should have posted that earlier. – Tim Biegeleisen Dec 01 '16 at 11:54
Hey guys ,,,I am getting my desired output only if my string length is 7,else it throws "String index out of range" .... Am stuck at the end of code {input.substring(x+6,7)} <<< String output = input.substring(x,x+2) + "00" + input.substring(x+2,x+4) + "00" + input.substring(x+4,x+6) + "00" + input.substring(x+6,7) + "00" >>> @jay – HelloWorld Dec 01 '16 at 12:01

0 Answers0