How to unwrap an Optional value?

Question

So I have this in my code.

let hex:String = "#FFFFFF"
var returnValue = UInt()
var newString = String()

newString = hex.replacingOccurrences(of: "#", with: "0x")
returnValue = UInt(newString)! //This line gets an error

It gives me an unwrapping optional value error. How do I fix it?

Possible duplicate of [What does "fatal error: unexpectedly found nil while unwrapping an Optional value" mean?](http://stackoverflow.com/questions/32170456/what-does-fatal-error-unexpectedly-found-nil-while-unwrapping-an-optional-valu) — Hamish, Dec 01 '16 at 12:24

score 0 · Answer 1 · answered Dec 01 '16 at 12:37

0

You are using the wrong initializer and even if it was the right initializer the string format is wrong:

let hex = "#FFFFFF"
let newString = hex.replacingOccurrences(of: "#", with: "")
let returnValue = UInt(newString, radix:16) ?? 0

answered Dec 01 '16 at 12:37

vadian

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How to unwrap an Optional value?

1 Answers1