Integer.parseInt() crashes Java program

Question

I am trying to use Integer.parseInt() to convert a String into an int, and if that doesn't work, catch the NumberFormatException that the program returns and reprompt the user.

However, when I enter a non-String value, instead of reprompting me, the program freezes.

Here is my code snippet:

    keepLooping = true;
    while(keepLooping) {
      String unconvertedString = "";
      int convertedInt = 0;
      try {
        System.out.print("Enter a string to be parsed into an integer: ");
        unconvertedString = userInput.next();
        convertedInt = Integer.parseInt(unconvertedString);
        keepLooping = false;
      }
      catch (NumberFormatException e) {
        userInput.next();
      }
    }

So it works correctly when you provide an int? What exactly is userInput? — Reisclef, Dec 04 '16 at 19:21
Possible duplicate of [What is a NumberFormatException and how can I fix it?](http://stackoverflow.com/questions/39849984/what-is-a-numberformatexception-and-how-can-i-fix-it) — xenteros, Dec 05 '16 at 10:54

score 0 · Accepted Answer · answered Dec 04 '16 at 19:35

0

You need to get rid of the userInput.next() in the catch clause.

catch (NumberFormatException e) {
    //userInput.next();
}

Just let it continue the loop if exception occurs.

answered Dec 04 '16 at 19:35

Nick

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Integer.parseInt() crashes Java program

1 Answers1