i need to convert the following statement to
x = 123456.789;
and print the floating point variable x with 3 digits before the decimal point and two digits after the decimal point.
output
456.78
What i have tried printf("%6.2f",x);
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What if you use the modulo operator `%`? – lmiguelvargasf Dec 05 '16 at 01:14
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@Imiguelvargasf how? – Venkat Dec 05 '16 at 01:17
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sorry for my mistake, it seems you have to use `fmod()` with floats in order to get the modulo operation result. – lmiguelvargasf Dec 05 '16 at 01:19
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Possible duplicate of [Rounding Number to 2 Decimal Places in C](http://stackoverflow.com/questions/1343890/rounding-number-to-2-decimal-places-in-c) – David Rawson Dec 05 '16 at 05:50
1 Answers
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floating point variable x with 3 digits before the decimal point and two digits after the decimal point.
What you need is floating-point modulo remainder function fmod
double x = 123456.789;
double y = fmod( x, 1000 );
printf("%06.2f",y);
Remember to #include <math.h>, and compile with -lm for the math library, example:
gcc test.c -o test -lm
artm
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Try `printf("%3.2f",1.234);`. Suggest to "3 digits before the decimal point", use `printf("%06.2f",1.234);` 6 is the minimum width. 0 is the left padding – chux - Reinstate Monica Dec 05 '16 at 05:31
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