Scala - build with hashmap

Question

I made hashmap that contains varous type of data in java and would like to pass it to scala.

In java

HashMap<String, Object> myMap = new HashMap<String, Object>();

In scala

def myApp(myMap: HashMap[String, Any]) // Object -> Any

The hashmap was passed well and used it like below.

val aValue = myMap.getOrDefault("A", "a").asInstanceOf[String]
val bValue = myMap.getOrDefault("B", new Hashmap[String, String]).asInstanceOf[ Hashmap[String, String]]

It wored as I expected, BUT when I tried to build it with gradle to make a jar. It came with this error.

[ant:scalac] myApp.scala:44: error: value getOrDefault is not a member of java.util.HashMap[String, Any]
[ant:scalac]  Note: implicit method myEncoder is not applicable here because it comes after the application point and it lacks an explicit result type
[ant:scalac]         val aValue = myMap.getOrDefault("A", "a").asInstanceOf[String]
[ant:scalac]                            ^

What version of Java are you using? `getOrDefault` is from Java 8 — 4castle, Dec 05 '16 at 05:41
I changed project > java Compiler > jdk compliance > JDK compliance as 1.8, but got still same error. — J.Done, Dec 05 '16 at 06:06
See [this question](http://stackoverflow.com/q/24947844/5743988) — 4castle, Dec 05 '16 at 06:09
Are you building with Gradle from Eclipse or from command line? — Alexey Romanov, Dec 05 '16 at 06:35
On eclipse. for double check, i changed JAVA_HOME path as jdk 1.8, but still same error. — J.Done, Dec 05 '16 at 06:36
I figured it out. It ran with 'gradle wrapper's default' . I changed it from 'run as' > 'gradle build' > arguamets > worksapce JRE as jdk 1.8. Now need to find out where gradle wrapper's default is set and how to change. thanks :) — J.Done, Dec 05 '16 at 06:39
It's on build.gradle. Everythings works well. you saved me :) — J.Done, Dec 05 '16 at 06:40

score 0 · Accepted Answer · answered Dec 05 '16 at 06:52

0

Can you try something like this below:

import collection.JavaConverters._
import collection.mutable._

def myApp(myMap: java.util.HashMap[String, Any])=

{

val scalaHashMap=myMap.asScala

}

answered Dec 05 '16 at 06:52

A srinivas

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Scala - build with hashmap

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