How to concatenate php variable with json_decoded variable

Question

Am getting json object and receiving in php using file_get_contents().

$getAddEntryData = json_decode(file_get_contents("php://input"));

The problem is i have to concatenate php variable with received object.

If it's a php REQUEST object we are doing like this.

$timingsStatus = $_REQUEST['timings_'.$dayArray[$i].'_status'];

But how can i do with json decoded object.

i tried something like this ->.

$timingsStatus = $getAddEntryData->timings_.$dayArray[$i]._status;

Its not working, how can concat like this?.

Here is my structure of json data.

let data = {
        timings_enabled : this.form_data.map_timings,

        timings_mon_status : this.form_data.map_timings_mon_status,
        timings_mon_from : this.form_data.map_timings_mon_from,
        timings_mon_to : this.form_data.map_timings_mon_to,


        timings_tue_status : this.form_data.map_timings_tue_status,
        timings_tue_from : this.form_data.map_timings_tue_from,
        timings_tue_to : this.form_data.map_timings_tue_to,


        timings_wed_status : this.form_data.map_timings_wed_status,
        timings_wed_from : this.form_data.map_timings_wed_from,
        timings_wed_to : this.form_data.map_timings_wed_to,


        timings_thu_status : this.form_data.map_timings_thu_status,
        timings_thu_from : this.form_data.map_timings_thu_from,
        timings_thu_to : this.form_data.map_timings_thu_to,


        timings_fri_status : this.form_data.map_timings_fri_status,
        timings_fri_from : this.form_data.map_timings_fri_from,
        timings_fri_to : this.form_data.map_timings_fri_to,


        timings_sat_status : this.form_data.map_timings_sat_status,
        timings_sat_from : this.form_data.map_timings_sat_from,
        timings_sat_to : this.form_data.map_timings_sat_to,

        timings_sun_status : this.form_data.map_timings_sun_status,
        timings_sun_from : this.form_data.map_timings_sun_from,
        timings_sun_to : this.form_data.map_timings_sun_to

    }

PHP code what am trying to do.

$getAddEntryData = json_decode(file_get_contents("php://input"));
$dayArray = array('mon', 'tue', 'wed', 'thu', 'fri', 'sat', 'sun');

if (isset($getAddEntryData->timings_enabled)) {

    for ($i = 0; $i < count($dayArray); $i++) {

        //$timingsStatus = $_REQUEST['timings_'.$dayArray[$i].'_status'];
        $timingsStatus = $getAddEntryData->timings_.$dayArray[$i]._status;

        $source = str_replace('[[TIMINGS-STATUS]]', "Available", $source);

        if ($timingsStatus == 'Open') {

           // $timingsFromTime = $_REQUEST['timings_'.$dayArray[$i].'_from'];
            $timingsStatus = $getAddEntryData->timings_.$dayArray[$i]._from;


           // $timingsToTime = $_REQUEST['timings_'.$dayArray[$i].'_to'];
            $timingsStatus = $getAddEntryData->timings_.$dayArray[$i]._to;

            $source = str_replace('[[TIMINGS-'.strtoupper($dayArray[$i]).'-STATUS]]', $timingsStatus, $source);
            $source = str_replace('[[TIMINGS-'.strtoupper($dayArray[$i]).'-FROM]]', $timingsFromTime, $source);
            $source = str_replace('[[TIMINGS-'.strtoupper($dayArray[$i]).'-TO]]', $timingsToTime, $source);

        } else {

            $source = str_replace('[[TIMINGS-'.strtoupper($dayArray[$i]).'-STATUS]]', $timingsStatus, $source);
            $source = str_replace('[[TIMINGS-'.strtoupper($dayArray[$i]).'-FROM]]', "", $source);
            $source = str_replace('[[TIMINGS-'.strtoupper($dayArray[$i]).'-TO]]', "", $source);

        }

    }

}

can you include the structure of your decoded json – Beginner Dec 05 '16 at 06:19 — Beginner, Dec 05 '16 at 06:19
Seems your json is not valid... – Naga Dec 05 '16 at 06:28 — Naga, Dec 05 '16 at 06:28

score 2 · Accepted Answer · answered Dec 05 '16 at 06:34

2

Try with -

$timingsStatus = $getAddEntryData->{'timings_' . $dayArray[$i] . '_status'};

answered Dec 05 '16 at 06:34

Sougata Bose

31,517
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http://stackoverflow.com/questions/2596837/curly-braces-in-string-in-php will help – Sougata Bose Dec 05 '16 at 06:37

Beginner · Answer 2 · 2016-12-05T06:37:39.343

0

to do that just change your, this function will convert your json into an array

$getAddEntryData = json_decode(file_get_contents("php://input"));

to

$getAddEntryData = json_decode(file_get_contents("php://input"), true);

so this concatination works

$timingsStatus = $getAddEntryData['timings_'.$dayArray[$i].'_status'];

edited Dec 05 '16 at 06:37

answered Dec 05 '16 at 06:29

Beginner

4,118
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this and all i have done @Newbee only porblem with concat – Amruth Dec 05 '16 at 06:32
@AppuAmruth did you tried and does it solve? yes. that's all you have to do. – Beginner Dec 05 '16 at 06:32

score -1 · Answer 3 · answered Dec 05 '16 at 06:27

A "JSON decoded" object, is a simple object of PHP StdClass. That means you can simply use it accessing propreties (public). If you're not used to object, you can "decode" your JSON in an associative array. In this case, you add a second parameter to your json_decode(string, true)

This cannot work because PHP objects use the "arrow" -> operator to access properties/methods

$getAddEntryData->timings_->$dayArray[$i]->_status;

If your lost with your structure, I recommend you to always use "var_dump($variable)", one of the best help you can have there.

FYI, don't use $_REQUEST in PHP, but prefer POST, GET, SERVER... which are much better and always valid.

How to concatenate php variable with json_decoded variable

3 Answers3