Hibernate - scan entities

Question

I'm entry level Java developer and I have project with Hibernate and property file hibernate.cfg.xml like this

<?xml version="1.0" encoding="utf-8" ?>
<!DOCTYPE hibernate-configuration PUBLIC                            
    "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
    "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
    <session-factory>
        <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
        <property name="hibernate.connection.url">jdbc:mysql://localhost:3306/account?useSSL=false</property>
        <property name="hibernate.connection.password">root</property>
        <property name="hibernate.connection.username">root</property>
        <property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>
        <property name="show_sql">true</property>
        <property name="hbm2ddl.auto">create</property>
        <mapping class="ua.com.vtkachenko.entity.Group"></mapping>
        <mapping class="ua.com.vtkachenko.entity.Movement"></mapping>
        <mapping class="ua.com.vtkachenko.entity.Product"></mapping>
        <mapping class="ua.com.vtkachenko.entity.Description"></mapping>
    </session-factory>
</hibernate-configuration>

How I can set auto scanning of entity classes and delete this rows?

<mapping class="ua.com.vtkachenko.entity.Group"></mapping>
<mapping class="ua.com.vtkachenko.entity.Movement"></mapping>
<mapping class="ua.com.vtkachenko.entity.Product"></mapping>
<mapping class="ua.com.vtkachenko.entity.Description"></mapping>

From the DTD: `<!ATTLIST mapping package CDATA #IMPLIED>` so `` — , Dec 05 '16 at 12:37
I replace snippet of code : ` ` by `` but it still don't work. @RC — Vlad, Dec 05 '16 at 13:44

score 0 · Answer 1 · answered Dec 05 '16 at 12:51

0

When you define sessionfactory bean in spring context file, you can use packagesToScan property and @Entity annotation to achieve this.

Code snippet:

<bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
  <property name="dataSource" ref="dataSource" />
  ... //other properties
  <property name="packagesToScan" value="ua.com.vtkachenko.entity">
  ../other properties
</bean>

Now write @Entity annotation above entity classes. Also your entity class should have @Column annotation to get mapped with table columns.

Hope it helps. If you any issue, please let me know.

answered Dec 05 '16 at 12:51

SachinSarawgi

2,632
20
28

I insert this into my app-context.xml and get error _Exception in thread "main" org.hibernate.MappingException: Unknown entity: ua.com.vtkachenko.entity.Group at org.hibernate.impl.SessionFactoryImpl.getEntityPersister(SessionFactoryImpl.java:548)..............._ – Vlad Dec 05 '16 at 13:51
I think that it is correct way to solve it when you use Spring with Hibernate. In my example I have such project structure ![Screenshot](https://s18.postimg.org/w29vccrih/Screenshot_from_2016_12_05_16_16_19.png). – Vlad Dec 05 '16 at 14:22

score 0 · Answer 2 · answered Dec 05 '16 at 13:44

0

I would suggest you to learn instead of this: Spring boot and JPA.

It would save you many headaches if your aim is just learning, imho.

Regards

answered Dec 05 '16 at 13:44

Marco Tulio Avila Cerón

400
1
3
18

Spring Boot and JPA indeed provides a really neat quickstart, but then I got severe headaches while fighting with injections and debugging Spring (Spring is HUGE and overwhelming). I eventually gave up and stopped using Spring and JavaEE altogether, and moved to this: https://github.com/mvysny/vaadin-on-kotlin (disclaimer - I'm the author) – Martin Vysny Jan 25 '17 at 07:54

score 0 · Answer 3 · edited May 23 '17 at 12:01

0

Or, if you don't want to use Spring, here's a solution with pure Hibernate on JavaSE - this will scan your entire classpath for JPA entities: https://stackoverflow.com/a/41845759/377320

edited May 23 '17 at 12:01

Community

1
1

answered Jan 25 '17 at 07:31

Martin Vysny

3,088
28
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Hibernate - scan entities

3 Answers3