Opening a Separate JavaFX Window from a Separate Class

Question

So I'm trying to open a second JavaFX window on a specific button click to perform a separate function. How should I proceed given the code below from my MainGUI and attempting to link a class titled NearLocationsGUI which would open when the button is clicked:

        Button nearMe = new Button();
        nearMe.setText("Find Locations Near Me");


        nearMe.setOnAction(new EventHandler<ActionEvent>() {
            @Override
            public void handle(ActionEvent event) {
                System.out.println("Locations Near Me Found!");
                NearestLocationsGUI.launch();
            }
        });

Not a duplicate of this post: JavaFX open new window because that was working with FXML, which I am not, and creating a new window in the same class, I have an in depth second class I need to open- almost like a second application.

Not a duplicate- that was utilizing FXML not a standard JavaFX class — SN44, Dec 05 '16 at 20:48

score 2 · Answer 1 · answered Dec 05 '16 at 20:49

2

You just have create a new stage then say newStage.show();

answered Dec 05 '16 at 20:49

MadMax

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What would I use as the argument for Show? – SN44 Dec 05 '16 at 20:52
1

[`show()`](https://docs.oracle.com/javase/8/javafx/api/javafx/stage/Stage.html#show--) has no arguments. – jewelsea Dec 05 '16 at 20:52

Opening a Separate JavaFX Window from a Separate Class

1 Answers1