I have the following code
dt.ajax.url( 'test.php?status=' ).load();
I defined a variable
var status= 55
I wand to add status_2
in the link like this
dt.ajax.url( 'test.php?status=&status' ).load();
How can I do it ?
I have the following code
dt.ajax.url( 'test.php?status=' ).load();
I defined a variable
var status= 55
I wand to add status_2
in the link like this
dt.ajax.url( 'test.php?status=&status' ).load();
How can I do it ?
Try this. You need to concatenate
the variable with url
dt.ajax.url('test.php?status='+status).load();