Asking user for input - prime number code

Question

num = 3    #take input from the user
if num > 1: # if input is greater than 1 check for factors
   for i in range(2,num):
       if (num % i) == 0:
               print(num,"is not a prime number")
               break
   else:
       print(num,"is a prime number")
            #if input number is less than or equal to 1, it is not prime

else:
   print(num,"is not a prime number")

I have my code here which works out the prime number of the num section, what I need to do it ask the user for the input when I run the code.

Did you do any searching at all? – Karnage Dec 07 '16 at 09:31 — Karnage, Dec 07 '16 at 09:31

score 0 · Accepted Answer · answered Dec 07 '16 at 09:31

0

This is pretty straightforward:

num = int(input("Input a number: "))

answered Dec 07 '16 at 09:31

ForceBru

43,482
10
63
98

No need for the `int()` unless you want to handle errors – Seif Dec 07 '16 at 09:33
1

@Saksow, the OPs code is clearly in Python 3.x – ForceBru Dec 07 '16 at 09:36
@Saksow That depends on the Python version. Casting it to an int will make it work in Python 2 and 3. – Klaus D. Dec 07 '16 at 09:36
Yes I was using Python 2.x, thanks – Seif Dec 07 '16 at 09:36
1

Python 2 `input()` evaluates the user input as an expression, `raw_input()` returns a string. Python 3 `input()` returns a string no matter what. – Guillaume Dec 07 '16 at 09:37

score 0 · Answer 2 · answered Dec 07 '16 at 09:33

Since input() always assumes that it's taking a string ,you have to convert it to int :

print("Enter a number:")
num = int(input())   #this here
if num > 1: # if input is greater than 1 check for factors
   for i in range(2,num):
       if (num % i) == 0:
               print(num,"is not a prime number")
               break
   else:
       print(num,"is a prime number")
            #if input number is less than or equal to 1, it is not prime

else:
   print(num,"is not a prime number")

Asking user for input - prime number code

2 Answers2