How would the output of
int i = 6;
i += ++i + ++i + i++ + --i;
printf("%d", i);
be evaluated. When I do it on paper I get 39. But the output after executing is 40.
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deezpeeps
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This will produce an undefined behavior. – Surajeet Bharati Dec 07 '16 at 15:42
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@Surajeet Bharati why? Is anything in it ambiguous? – deezpeeps Dec 07 '16 at 15:43
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Duplicate of http://stackoverflow.com/questions/949433/why-are-these-constructs-using-undefined-behavior?noredirect=1&lq=1 – Surajeet Bharati Dec 07 '16 at 15:45
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Also look into this . http://stackoverflow.com/questions/4176328/undefined-behavior-and-sequence-points – Surajeet Bharati Dec 07 '16 at 15:50