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If I want to store an Algebraic Data Type (ADT) (ie a Scala sealed trait hierarchy) within a Spark DataSet column, what is the best encoding strategy?

For example, if I have an ADT where the leaf types store different kinds of data:

sealed trait Occupation
case object SoftwareEngineer extends Occupation
case class Wizard(level: Int) extends Occupation
case class Other(description: String) extends Occupation

Whats the best way to construct a:

org.apache.spark.sql.DataSet[Occupation]
zero323
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Ben Hutchison
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2 Answers2

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TL;DR There is no good solution right now, and given Spark SQL / Dataset implementation, it is unlikely there will be one in the foreseeable future.

You can use generic kryo or java encoder

val occupation: Seq[Occupation] = Seq(SoftwareEngineer, Wizard(1), Other("foo"))
spark.createDataset(occupation)(org.apache.spark.sql.Encoders.kryo[Occupation])

but is hardly useful in practice.

UDT API provides another possible approach as for now (Spark 1.6, 2.0, 2.1-SNAPSHOT) it is private and requires quite a lot boilerplate code (you can check o.a.s.ml.linalg.VectorUDT to see example implementation).

zero323
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    why is kryo hardly useful in practice? Is it because we have to specify kryo serializer after every transformation? – user2103008 Jun 28 '21 at 23:40
2

I have once dived deeply into the subject and created a repo showcasing all the approaches I have found could be useful.

Link: https://github.com/atais/spark-enum

Generally, zero323 is right, but you might find it useful to understand the full picture.

Atais
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