Generating a result in range of two random integers in range

Question

For a school assignment I have to choose two random integers from 0 to 20 and its result (through sub or add which also chooses random) must be in range 0 to 20. For integers and operations I used:

def random():
    op={"-": operator.sub, "+": operator.add}
    a = random.randint (0,20)
    b = random.randint (0,20)

    ops = random.choice(list(op.keys()))
    answer=op[ops](a,b)
    return answer

Source link for the above code: How can I randomly choose a maths operator and ask recurring maths questions with it?

But i have no idea how to use it in such a way that it can give a result only in range of 0 to 20. Python v3.0 beginner.

do what you do in a while loop until your result is satisfactory is one approach. — themistoklik, Dec 08 '16 at 07:10

score 1 · Accepted Answer · answered Dec 08 '16 at 07:12

If I am understanding your question correctly, you only want your function to return a result if that result is between 0 and 20. In that case, you could use a while loop until your condition is satisified.

def random():
    while True:
        op={"-": operator.sub, "+": operator.add}
        a = random.randint (0,20)
        b = random.randint (0,20)

        ops = random.choice(list(op.keys()))
        answer=op[ops](a,b)
        if answer in range(0,20):
            return answer

score 0 · Answer 2 · answered Dec 08 '16 at 07:13

0

Wrap it in a while as suggested or you could try bounding the second random var as such

a = random.randint (0,20)
b = random.randint (0,20-a)

To ensure you never run out of range.

answered Dec 08 '16 at 07:13

themistoklik

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score 0 · Answer 3 · answered Dec 08 '16 at 07:34

0

You can also use

for ops in random.sample(list(op), len(op)):
    answer = op[ops](a, b)
    if 0 <= answer <= 20:
        return answer
raise RuntimeError('No suitable operator')

answered Dec 08 '16 at 07:34

Gribouillis

2,230
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score 0 · Answer 4 · answered Dec 08 '16 at 07:35

You can add modulo 20 operation on the result, so that the result always stays in interval [0, 20):

def random():
    op={"-": operator.sub, "+": operator.add}
    a = random.randint (0,20)
    b = random.randint (0,20)

    ops = random.choice(list(op.keys()))
    answer=op[ops](a,b)

    return answer % 20

score 0 · Answer 5 · answered Dec 08 '16 at 07:50

You can try to ensure that result will be inside of the bounds, but rules are different for each operation here:

op = {"-": operator.sub, "+": operator.add}
ops = random.choice(list(op))
if ops == '+':
    a = random.randint(0, 20)      # a in [0; 20]
    b = random.randint(0, 20 - a)  # b in [0; 20 - a]
else:  # ops == '-'
    a = random.randint(0, 20)  # a in [0; 20]
    b = random.randint(0, a)   # b in [0; a]

answer = op[ops](a, b)  # answer will be in [0; 20]
print(a, ops, b, '=', answer)

Generating a result in range of two random integers in range

5 Answers5