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python always answers you are likely to be eligible for work even though I typed a number under 18 

question1= raw_input("are you fat?")
if question1== ("yes"):
    print ("sorry you are not fit for work")
elif question1== ("no"):
    print ("you may be eligible for work, move on to the next question please")
    question2= raw_input("how old are you?")
    if question2 >= 18:
        print ("you are likely to be eligible for work")
    elif question2 < 18:
        print ("sorry come back when you're older")
inspectorG4dget
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jacky
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2 Answers2

1

That would be because raw input is asking for a undefined string of characters not an integer when python takes in the output it receives 

question2 = "16"

Rather than

question2 = 16

Here would be a fix to your code: 

question1= raw_input("are you fat?")
if question1== ("yes"):
    print ("sorry you are not fit for work")
elif question1== ("no"):
    print ("you may be eligible for work, move on to the next question please")
    question2= int(raw_input("how old are you?"))
        if question2 >= 18:
            print ("you are likely to be eligible for work")
        elif question2 < 18:
            print ("sorry come back when you're older")

Because now python converts the string into an integer

question2= int(raw_input("how old are you?"))

I would recommend using python 3 though (This is my opinion) It makes this simpler

-Joshua

Merhlim
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You are comparing a string (question2) and an integer (18). Contrary to other languages like PHP, the string is not automatically converted to an int beforehand, and the int is not converted to a string either.

In such a comparison, an int is always < a string. You must compare int(question2) with 18.

See here for the full explanation.

Community
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xhienne
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