Read characters till end of line

Question

Can someone please give me a simple answer on how do I read a characters till the end of the line? I have tried typing

cin >> CHAR;

if (CHAR == '\n' || CHAR == '\0') cout << "?" << endl;

and none of this work for me, it just ignores this and reads further.

Do you [search](http://stackoverflow.com/questions/7868936/read-file-line-by-line)? — Stargateur, Dec 09 '16 at 22:56
I have been searching but what I find is too advanced and difficult for me, all I need is a simple answer, this has been bothering me for a couple of weeks — andrewc, Dec 09 '16 at 22:59
Start with the [documentation](http://en.cppreference.com/w/cpp/io). — Captain Obvlious, Dec 09 '16 at 22:59
Your use of `CHAR` as a variable name is poor coding standard. You should have you variable names differ from keywords by more than one case. Often, readers of your code may think that `CHAR` is a typo of the keyword `char`. — Thomas Matthews, Dec 09 '16 at 23:16
@umadlol "couple of weeks", "read line cpp" in google. You **REALLY** need to learn how to search. — Stargateur, Dec 09 '16 at 23:32
possible dupe: [How to read until EOF from cin in C++](http://stackoverflow.com/q/201992/1248974) — chickity china chinese chicken, Dec 10 '16 at 00:15

score 0 · Answer 1 · answered Dec 10 '16 at 17:33

As a simple solution, you can do something along the lines of:

std::string s;
std::getline(std::cin, s));
for(const char& c : s){
    // Do something with the character
}

This will read a single line from std::cin and then loop through each character of the line.

1 Answers1