Python try -except in raw_input()

Question

What is wrong with the following code? I get an error.

largest = 0
smallest = 0

while True:
    num = raw_input("Enter a number: ")

    try:
        num = int(num)
        if num == 'done':
            break 
    except:
        print('Invalid input')
        continue

    if num < smallest:
        smallest = num

    if num > largest:
        largest = num

print('Maximum is ', largest)
print('Minimum is ', smallest)

Whenever I'm trying to take string as input its showing 'NamEerror' — mmrbulbul, Dec 10 '16 at 20:13
Thanks for the suggestion. But still get an error . http://ideone.com/nNJ0DZ — mmrbulbul, Dec 10 '16 at 20:25

score 2 · Accepted Answer · edited May 23 '17 at 12:24

2

In the future, please include your error messages in the question. This is your error:

Traceback (most recent call last):
  File "./prog.py", line 5, in <module>
NameError: name 'raw_input' is not defined

That's because in Python 3 raw_input() was renamed to input().

edited May 23 '17 at 12:24

Community

1
1

answered Dec 10 '16 at 20:29

Xiong Chiamiov

13,076
9
63
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score 1 · Answer 2 · answered Dec 10 '16 at 20:29

1

You are trying to run a Python 2 application with a Python 3 interpreter.

answered Dec 10 '16 at 20:29

Alexander

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Python try -except in raw_input()

2 Answers2