Sort an array of tuples in swift 3

Question

Hi I have the following

class MyClass {
  var myString: String?
}

var myClassList = [String: MyClass]()

I would like to sort this array alphabetically by the myString variable in Swift 3 any pointers?

Answer 1

As mentioned above, you have a dictionary, not tuples. However, Dictionaries do indeed have a sorted(by:) method that you can use to sort an array of Key/Value pair tuples. Here's an example:

var m: [String: Int] = ["a": 1]
let n = m.sorted(by: { (first: (key: String, value: Int), second: (key: String, value: Int)) -> Bool in
  return first.value > second.value
})

That's expanded to show the full signature of the closure, however easily shorthanded to:

let n = m.sorted(by: {
  return $0.value > $1.value
})

Additionally, you can also perform other enumerations over Dictionaries

m.forEach { (element: (key: String, value: Int)) in
  print($0.value)
}

All of this is due to the Collection and sequence protocol hierarchies in Swift, they're some pretty nice abstractions.

Answer 2

Cool problem! Though i'd like to point out first that [String: MyClass] is a Dictionary and not at Tupule.

Swift does, however, support Tupules. The syntax for your tupule would look like so:

var tupule: (String, MyClass) = (foo, bar)

You would then need to make an Array of them:

var tupules:[(String, MyClass)] = [(foo, bar), (up, dog)]

Then you could sort that array:

tupules.sort({ $0[1].myString > $1[1].myString })

though you should probably define a more robust sort mechanism.

These are the contents of the sort closure:

$0 is the one of the objects for which needs to be compared, $1 is the other. $0[1] and $1[1] accesses the objects' 1 index, in this case, as defined in your tupule, it is your custom object MyClass

Hope this helps.

Answer 3

Swift version 5.2.4

let arr = [(0, 5), (1, 2), (2, 4), (3, 1), (4, 3)] // -> [(3, 1), (1, 2), (4, 3), (2, 4), (0, 5)]
let sorted = arr.sorted{ $0.1 < $1.1 }