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I wanted to know if it was possible to code that kind of line in a BASH program I would like to have something that looks like:

if set -e
    echo "Error"
fi

Actually my teacher just told that set -e stops the program when there is an error. I don't really know how it works. What I want is that when there is an error at any part of the program it does echo "Error"

I'm just learning how to use bash so my knowledge isn't very good yet.

Dnartreb925
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2 Answers2

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What I want is that when there is an error at any part of the program it does echo "Error"

You can use a trap:

trap "echo Error" ERR
cat ./file_that_doesnt_exist
echo "something after the error"

If you use this in combination with set -e the program will display the message and immediately exit - i.e. the echo won't run.

arco444
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  • Actually my teacher just told that set -e stops the program when there is an error. I don't really know how it works. What I want is that when there is an error at any part of the program it does `echo "Error" ` – Dnartreb925 Dec 13 '16 at 15:35
  • Ah, bad memory on my part. – chepner Dec 13 '16 at 16:17
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You can install a trap handler to execute custom code.

set -e
trap 'echo "Error $?"' ERR

...

# Simulate a command that fails by calling `exit` in a subshell.
(exit 3)
John Kugelman
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