javascript async/await in a generic loop

Question

Is this the correct implementation?

        let times= async (n,f)=>{while(n-->0) await f();} 

        times(5,()=>
               myfunc([1,2,3],err => err)
              )

myfunc is itself an async function awaiting for various other functions:

async myfunc(params,cb){

   await a( err => err )
   await b( err => err )
   await c( err => err )

}`

`async/await` doesn't make code synchronous. It just enables a more convenient way of writing asynchronous code. And yeah, that looks like it should work (why don't you just try it?), although I'd rather write `async () => await myfunc([1,2,3],err => err)`. — Felix Kling, Dec 14 '16 at 00:19
What do you mean by "make synchronous"? Or is it a typo and you meant asynchronous? — Bergi, Dec 14 '16 at 01:16
That `err => err` callback you are passing but not using anywhere does not look like correct usage of `async function`s. — Bergi, Dec 14 '16 at 01:17

score 10 · Accepted Answer · answered Dec 14 '16 at 01:21

10

Is this the correct implementation?

Yes. await works in loops like you'd expect it to, if that was your actual question.
I would however recommend to write

async function times(n, f) {
    while (n-- > 0)
        await f();
}

answered Dec 14 '16 at 01:21

Bergi

1 Answers1