Implicitly unwrapped optional in Swift

Asked Dec 14 '16 at 09:36

Active Dec 14 '16 at 09:42

Viewed 48 times

I am newbie for Swift and I have question about Implictly Unwrapped Optional on Swift. And sorry for unpretty format, I'm also newbie for stackoverflow.

let x: Int! = 1
print("\(x)")

Above Swift codes print "Optional(1)". I think that should print "1" since the constant "x"`s type is "Int!" rather than "Int?" to implicitly unwrap from followed codes. But it prints "Optional(1)".

I ran that code on IBM Swift Sandbox.

What's wrong with it?

asked Dec 14 '16 at 09:36

홍한석

See http://stackoverflow.com/a/39537558/1271826 – Rob Dec 14 '16 at 09:41
In Swift 3 the behavior for implicitly unwrapped optionals has changed. While in Swift 2 the optional got always unwrapped when used, in Swift 3 the IUO will get converted to a normal optional when possible. – Sulthan Dec 14 '16 at 09:43
Thanks for comments all! – 홍한석 Dec 14 '16 at 10:29

Implicitly unwrapped optional in Swift

0 Answers0