Java timestamp to php timestamp

Question

I want to convert a Java timestamp into a php timestamp. I have a java code that creates a JSON Object and send the content of this object to a php-page, which should store them into a database.

My problem is, that the timestamps are different.

Java:

Wed Dec 14 14:06:07 CET 2016

The output (as long converted):

1481720767015

On php I tried two different solutions:

PHP:

echo date('d.m.Y H:i:s', intval("1481720767015")/1000);
echo "<br>".gmdate('d.m.Y H:i:s', intval("1481720767015")/1000);

The output:

14.12.2016 08:06:07
14.12.2016 13:06:07

So how can I change the timezone to get the second output to the right time/timezone?

score 1 · Answer 1 · edited May 23 '17 at 12:30

1

There is a similar problem here : PHP date(); with timezone?

And the solution is - you need to pass the timezone when creating the date object like below :

$tz = 'Europe/London';
$timestamp = time();
$dt = new DateTime("now", new DateTimeZone($tz)); //first argument "must" be a string
$dt->setTimestamp($timestamp); //adjust the object to correct timestamp
echo $dt->format('d.m.Y, H:i:s');

edited May 23 '17 at 12:30

Community

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1

answered Dec 14 '16 at 13:24

Tushar

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thank you. I found another solution: $time = gmdate('d.m.Y H:i:s', intval("1481720767015")/1000); $time = date('d.m.Y H:i:s', strtotime($time)+60*60); – Micha93 Dec 14 '16 at 13:30
Your example does not use any timezon but directly use some raw interval ;) – Tushar Dec 14 '16 at 13:32

score 0 · Answer 2 · answered Dec 14 '16 at 13:30

0

thank you. I found another solution:

$time = gmdate('d.m.Y H:i:s', intval("1481720767015")/1000);
$time = date('d.m.Y H:i:s', strtotime($time)+60*60);

answered Dec 14 '16 at 13:30

Micha93

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Java timestamp to php timestamp

2 Answers2