Why do I keep getting "java.net.MalformedURLException: no protocol"

Question

I've tried all different kind of combinations but I just don't get what it wants from me:

java.net.MalformedURLException: no protocol: <?xml version="1.0" encoding="UTF-8" standalone="yes"?><ds><ds>...
    at java.net.URL.<init>(URL.java:593)
    at java.net.URL.<init>(URL.java:490)
    at java.net.URL.<init>(URL.java:439)
    at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.setupCurrentEntity(XMLEntityManager.java:620)
    at com.sun.org.apache.xerces.internal.impl.XMLVersionDetector.determineDocVersion(XMLVersionDetector.java:148)
    at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:805)
    at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:770)
    at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:141)
    at com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(DOMParser.java:243)
    at com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(DocumentBuilderImpl.java:339)
    at javax.xml.parsers.DocumentBuilder.parse(DocumentBuilder.java:177)

I've looked at other questions but I don't get what is wrong with my XML.

This is the full XML (with some plain text removed):

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ds>
    <ds>
        <cue>ABGB : §§ 786 , 810 , 812 </cue>Die Kosten ... <cue>Anmerkung : </cue>
        ... <cue>Bestätigung von </cue>7 
        <Relation bewertung="1">Ob 56/10a </Relation>= Zak 
        <Relation bewertung="1">2010/773 , 440 </Relation>. 
    </ds>
</ds>

The producing code:

DocumentBuilderFactory icFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder icBuilder;

Document parse = null;

try {
    icBuilder = icFactory.newDocumentBuilder();             
    parse = icBuilder.parse(xmlString);
} catch (ParserConfigurationException e) {
    e.printStackTrace();
} catch (SAXException e) {
    e.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
}

because your xml **is not** an [URL](https://docs.oracle.com/javase/8/docs/api/java/net/URL.html) — , Dec 15 '16 at 15:42
You can't make a URL object from an XML string - needs to be an actual URL — OneCricketeer, Dec 15 '16 at 15:42
I'm voting to close this question as off-topic because because the answer is in URL javadoc: https://docs.oracle.com/javase/8/docs/api/java/net/URL.html — , Dec 15 '16 at 15:43
This seems pretty clear, really. What are you actually trying to do?! — Dave Newton, Dec 15 '16 at 15:43
you probably want https://docs.oracle.com/javase/8/docs/api/org/w3c/dom/Document.html — , Dec 15 '16 at 15:44
[Look here](http://stackoverflow.com/questions/33250982/no-protocol-malformed-url-exception-thrown-at-me-when-trying-to-parse-an-xml-str) — Stefan, Dec 15 '16 at 15:49

score 7 · Answer 1 · answered Dec 15 '16 at 15:54

7

The parse(String) method takes a uri pointing to an XML document, not its content.

In order to parse the content, you'll have to construct your own InputSource. E.g.:

parse = icBuilder.parse(new InputSource(new StringReader(xmlString)));

answered Dec 15 '16 at 15:54

Mureinik

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score 5 · Accepted Answer · answered Dec 15 '16 at 15:53

5

You're passing a String to icBuilder.parse(xmlString), so you're actually invoking DocumentBuilder.parse(String uri).

The method expects an URI and will try to parse it as such, while you're passing it some XML data.

answered Dec 15 '16 at 15:53

Aaron

24,009
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2

Why would you even *try* to call it `parseUri()`, am I right? – Stefan Falk Dec 15 '16 at 15:54
this is an explanation why it won't work, but it does not suggest a solution like Mureinik do – Shaybc Apr 09 '20 at 15:57

Why do I keep getting "java.net.MalformedURLException: no protocol"

2 Answers2