Set border to LinearLayout programmatically

Question

I need to set a border to a LinearLayout when the user click on it. Every solution I have tried so far change the color of all the LinearLayout, not just the border.

<LinearLayout
    android:id="@+id/linearlayout_main"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:layout_weight="1"
    android:clickable="true"
    android:paddingBottom="3dp"
    android:paddingLeft="10dp"
    android:paddingRight="3dp"
    android:paddingTop="10dp>
</LinearLayout>

and the code I have used to add the border :

GradientDrawable drawable = new GradientDrawable();
drawable.setShape(GradientDrawable.RECTANGLE);
drawable.setStroke(1, Color.BLACK);
relativelayout_main.setBackgroundDrawable(drawable);

Any suggestion?

score 0 · Answer 1 · edited May 23 '17 at 10:31

0

I would consider using a background resource item using a selector for clicked/not clicked state that uses a shape with a specific color/stroke width or something like that.

Something like what is listed here https://stackoverflow.com/a/8203840/3934023 but combined with the selector to use that only in the clicked state, like in this answer: https://stackoverflow.com/a/5295522/3934023.

edited May 23 '17 at 10:31

Community

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1

answered Dec 16 '16 at 01:58

Zach

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Thanks for the answer. I followed the instruction,I did get the border, but the inside is black. – stavros.3p Dec 16 '16 at 02:33
I tried inside the shape, but nothing changed – stavros.3p Dec 16 '16 at 02:35
Black is represented in hex with 000000, so that's behaving correctly. Please post what you have in your original post, I'll take a look. – Zach Dec 16 '16 at 02:37

Set border to LinearLayout programmatically

1 Answers1