Check an Array if it contains an integer in Java

Question

Is this possible and if so how would I do this correctly? Want to be able to check if it contains 1 and 2 and if so go on with the program.

import java.util.*;

public class test
{
    public static void main(String [] args) {
        int[] field = {1, 2};

        if (Arrays.asList(field).contains(1) && Arrays.asList(field).contains(2)) {
            System.out.println("Hello World!");
        }
   }
}

score 8 · Accepted Answer · answered Dec 17 '16 at 12:19

8

You can use IntStream in Java 8

if (IntStream.of(field).anyMatch(i -> i == 1) &&
    IntStream.of(field).anyMatch(i -> i == 2)) {
    // has a 1 and a 2

answered Dec 17 '16 at 12:19

Peter Lawrey

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Thank you works like a charm! – Mattias Wiberg Dec 17 '16 at 12:25
Why not use an or in the IntPredicate and have a one-liner answer? `if (IntStream.of(field).anyMatch(i -> i == 1 || I == 2)) {` – Philippe Gioseffi Jun 16 '20 at 09:31

score 1 · Answer 2 · answered Dec 17 '16 at 12:19

Arrays.asList works with generic types, the closest match for an int[] is Object. So you get a List of int[]. You could use IntStream in Java 8+ like

if (IntStream.of(field).anyMatch(x -> x == 1) && 
        IntStream.of(field).anyMatch(x -> x == 2)) {
    System.out.println("Hello World!");
}

Check an Array if it contains an integer in Java

2 Answers2