if any element in two arrays matches then return true?

Question

I've two arrays, one is my define array and another I process from the database. Is there any proper way to compare between those arrays?

From database:

$user_type = [0 => "public" 1 => "10x413" 2 => "12x432"]

Defined array:

$specificUser = ['10x410','10x411','10x412','10x413','10x414']

If any element matches, then return true, just like php in_array() function.

Show an example of the two arrays that have a common element. — AbraCadaver, Dec 18 '16 at 04:58
I've processed this array from database, $user_type = [ 0 => "public" 1 => "10x413" 2 => "12x432"] , and $specificUser = ['10x410','10x411','10x412','10x413','10x414'] this is my own define array — Rafid Shahriar, Dec 18 '16 at 05:03

AbraCadaver · Accepted Answer · 2016-12-18T05:20:15.917

1

Just loop and check as you would using in_array() to get the value that matches:

foreach($specificUser as $value) {
    if(in_array($value, $user_type)) {
        echo $value;
        //break; to stop checking, a match was found, or not to continue and see more
    }
}

Or to just test for any match:

if(array_intersect($specificUser, $user_type)) {
    // it's true :-)
}

edited Dec 18 '16 at 05:20

answered Dec 18 '16 at 05:09

AbraCadaver

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score 0 · Answer 2 · answered Dec 18 '16 at 05:11

I'm sure this has been asked and answered before, but here's a solution:

array() !== array_intersect($user_types, $specific_users);

Note: The array elements are compared using strict comparison, so two elements are considered matching only if they are the same type and value.

if any element in two arrays matches then return true?

2 Answers2