(PHP beginner) Can I use loop to assign variable ordinal number suffix?

Question

I want to assign variable name $filename1, $filename2, $filename3 so I write code like this

for ($i=1; $i <= 3; $i++) { 
$filename.$i = 'images/location/'.$i;
}

but It error.

Now I use array to fix problem. But anyway I still wonder, is it possible to assign variable name with ordinal number suffix by using loop?

$filename = array();
for ($i=1; $i <= 3; $i++) { 
$filename[] = 'images/location/'.$i;
}

an array is in most cases is the better option anyway – Dec 20 '16 at 02:51 — , Dec 20 '16 at 02:51

score 2 · Accepted Answer · answered Dec 20 '16 at 02:48

2

Yes it is possible.

e.g.

$i = 1;

${'filename' . $i} = 'apple';

echo $filename1; // prints apple

answered Dec 20 '16 at 02:48

aconnelly

score 0 · Answer 2 · answered Dec 20 '16 at 02:51

You CAN pass a variable as a variable name. The way to do so is with $$.

In your case, I would assign the variable name by concatenating the desired string, and then assign the variable in a separate line.

$filename = "filename" . $i;
$$filename = 'images/location/'.$i;

2 Answers2