How can i download a file from ajax call and force the results do be downloaded

Question

I have post the similar question yesterday and i haven't get the results. I have loaded data on my kendo grid and when i click download, i want to download the file but it is not returning results. The folder that i am downloading from is on the server not on project solution. I created a controller to test the download without a button click and it works but i want to download from kendo button click. No error on console

Function for getting the selected Id from the grid

 function showDetails(e) {
               e.preventDefault();
               var dataItem = this.dataItem($(e.currentTarget).closest("tr"));

               DownloadIndexController(dataItem.possID);
               }

Ajax call to the controller

function DownloadIndexController(possID) {
                $.ajax({
                    url: '@Url.Action("DownloadIndex", "Poss")',
                    type: "GET",
                    data: { possID: possID },
                    dataType: "json",
                    success: function (data) {
                        window.location = '@Url.Action("DownloadIndex", "Poss")';
                    }
                })
            }

Controller

public ActionResult DownloadIndex(int possID)
    {
        string Filelocation = "myserverlocation"
        FileContentResult ff = null;
        try
        {
            OnePossModel md = new Models.OnePossModel();
            JsonParamBuilder myBuilder = new JsonParamBuilder();
            myBuilder.AddParam<Guid>("submittingUserID", System.Guid.Parse(User.Identity.GetUserId()));
            myBuilder.AddParam<int>("possID", Convert.ToInt32(possID));

            string jsonReq = Models.JsonWrapper.JsonPOST(ApiBaseUrl + ApiPOSSSubBaseUrl + "/WritePOSSFile", myBuilder.GetJSonParam());
            string possFilename = Models.DeserialiseFromJson<string>.DeserialiseApiResponse(jsonReq);

            possFilename = possFilename.Replace(",", ",");

            string x = Filelocation + possFilename.ToString();

            var type = System.Net.Mime.MediaTypeNames.Application.Octet;

            byte[] fileBytes = System.IO.File.ReadAllBytes(x);
            string myfileName = possFilename;
            ff =  File(fileBytes, type,myfileName);
            Response.AppendHeader("Content-Disposition", "attachment; filename=" + myfileName);
            Response.BinaryWrite(fileBytes);
            return ff;
        }
        catch (Exception ex)
        {
            throw ex;
        }
    }

Why don't you *return* the FileResult generated by `File()` ? — Panagiotis Kanavos, Dec 20 '16 at 13:22

score 0 · Answer 1 · answered Dec 20 '16 at 13:31

0

In your controller, just add this:

public FileResult DownloadIndex(int possID)
{
    . . . .
    return File(fileBytes, type,myfileName);
}

answered Dec 20 '16 at 13:31

SᴇM

7,024
3
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I have made your changes and am still not getting results. even on console there's no error. i doesn't return anything – Mr Junior Dec 20 '16 at 13:36
Debug your method and make sure you have not empty bytearray – SᴇM Dec 20 '16 at 13:58
I have debug and it is not returning null. byte [] got data. – Mr Junior Dec 20 '16 at 14:02
Check popup blocker? – Scott Dobbins Dec 20 '16 at 15:12
I have checked my popup. the setting is disabled – Mr Junior Dec 20 '16 at 19:43

score 0 · Answer 2 · edited May 23 '17 at 11:45

0

I don't think it can be done the way you are trying to. Take a look here for a workaround to simulate "ajax file download".

In your code you are making 2 requests, the first creates the file and stream it in the response (and cant be downloaded with ajax), and then the second request by setting the window.location - But the file is not "alive" any more since it was allocated to the first response.

If using the FileResult Action then give away the ajax call (depends on your requirements) and just use a plain link: /poss/downloadindex/123

edited May 23 '17 at 11:45

Community

1
1

answered Dec 20 '16 at 17:51

Issac

943
1
6
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@Isasac I don't really understand what you saying. can you just modify the code so that i can understand on what you are saying. thanks – Mr Junior Dec 20 '16 at 19:45

How can i download a file from ajax call and force the results do be downloaded

2 Answers2