Relevant Regular Expression in scala

Question

I want to keep only the last term of a string separated by dots

Example:

My string is:

abc"val1.val2.val3.val4"zzz

Expected string after i use regex:

abc"val4"zzz

Which means i want the content from left-hand side which was separated with dot (.)

The most relevant I tried was

val json="""abc"val1.val2.val3.val4"zzz"""
val sortie="""(([A-Za-z0-9]*)\.([A-Za-z0-9]*){2,10})\.([A-Za-z0-9]*)""".r.replaceAllIn(json, a=>  a.group(3))

the result was:

abc".val4"zzz

Can you tell me if you have different solution for regex please?

Thanks

Maybe `json.replaceAll("(\\w+\")[^\"]*\\.([^\"]*\")", "$1$2")`? — Wiktor Stribiżew, Dec 21 '16 at 14:00

score 1 · Answer 1 · answered Dec 21 '16 at 14:20

1

You may use

val s = """abc"val1.val2.val3.val4"zzz"""
val res = "(\\w+\")[^\"]*\\.([^\"]*\")".r replaceAllIn (s, "$1$2")
println(res)
// => abc"val4"zzz

See the Scala demo

Pattern details:

(\\w+\") - Group 1 capturing 1+ word chars and a "
[^\"]* - 0+ chars other than "
\\. - a dot
([^\"]*\") - Group 2 capturing 0+ chars other than " and then a ".

The $1 is the backreference to the first group and $2 inserts the text inside Group 2.

answered Dec 21 '16 at 14:20

Wiktor Stribiżew

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Thanks for your help on that regex/eclipse question, too ;-) – GhostCat Dec 22 '16 at 08:07
Well,in real life, it's a big Json where some objects are prefixed with a domain name. For example: "bic3Reference":{"fr.laposte.colis.schema.pivot.common.parcel.ParcelReference":{"type":{"string":"c"},"ref":"b","key":{"string":"a"}}},"customerParcelReference":{"fr.laposte.colis.schema.pivot.common.parcel.CustomerParcelReference":{"ref":"CAB CY32"}} – jean-luc T Dec 22 '16 at 11:11
Then use approapriate tools, see [How to parse JSON in Scala using standard Scala classes?](http://stackoverflow.com/questions/4170949/how-to-parse-json-in-scala-using-standard-scala-classes) – Wiktor Stribiżew Dec 22 '16 at 11:18

Tzach Zohar · Answer 2 · 2016-12-21T14:04:32.557

0

Maybe without Regex at all:

scala> json.split("\"").map(_.split("\\.").last).mkString("\"")
res4: String = abc"val4"zzz

This assumes you want each "token" (separated by ") to become the last dot-separated inner token.

edited Dec 21 '16 at 14:04

answered Dec 21 '16 at 13:59

Tzach Zohar

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Well,in real life, it's a big Json where some objects are prefixed with a domain name – jean-luc T Dec 22 '16 at 11:03

Relevant Regular Expression in scala

2 Answers2