'invoke a function as a method' that is within another 'function as a method'

Question

I have inherited some javascript code that I am struggling to work with. I believe I need to 'invoke a function as a method' that is within another 'function as a method'. I have included abridged code below.

  drawer = {
  ...
  ChartDrawer: function(var1,var2,etc)
{
 ...
 this.drawChart = function(node)
    {
    ... 
        $(this.jqValToggle + ' #valuation-box').click(function(){
            console.log('clicked');
            drawer.valToggle();
            var targetNode = addrFromRawAddr(rawAddr)
            showNarrative(targetNode);
            /// THIS IS WHERE I'D LIKE TO CALL drawChart FROM
        });
    }
}

Could you please suggest the syntax needed to call 'drawChart' from the location in the code specified above.

I would have thought I could use drawer.ChartDrawer.drawChart(node); but this gets 'Uncaught TypeError: drawer.ChartDrawer.drawChart is not a function'. I have also tried variations on using 'this.drawChart' with no success

Almost a duplicate of [How to access the correct `this` inside a callback?](http://stackoverflow.com/questions/20279484/how-to-access-the-correct-this-inside-a-callback). It provides multiple solutions for accessing `this` inside a callback. — Felix Kling, Dec 22 '16 at 16:17
Try `return arguments.callee(node);` after showNarrative(targetNode) call — Medet Tleukabiluly, Dec 22 '16 at 16:26

score 3 · Accepted Answer · edited Dec 22 '16 at 16:15

3

Try this:

    $(this.jqValToggle + ' #valuation-box').click(function(){
        /* ... */
        this.drawChart();
    }.bind(this));

By forcing the click handler to run in the current context, rather than in the context of the clicked element, we retain access to the drawChart method.

edited Dec 22 '16 at 16:15

Felix Kling

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answered Dec 22 '16 at 16:00

Mitya

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@PaulTrotter: there was a typo in the code, have a look again. – Felix Kling Dec 22 '16 at 16:15
1

With Felix's correction to the syntax this works perfectly. Thank you both – Paul Trotter Dec 22 '16 at 16:25

'invoke a function as a method' that is within another 'function as a method'

1 Answers1