I am have read python documentations regarding list comprehensions I got an idea about list comprehensions work flow, but unable to understand the process involved in this code.
items=[x for x in raw_input().split(',')]
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It is not output, it is an assignment. – Anthon Dec 23 '16 at 10:13
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Run it and try it yourself – sameera sy Dec 23 '16 at 10:14
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What's the comprehension for? Isn't this equivalent to `items = raw_input().split(',')?` – Jérôme Dec 23 '16 at 10:17
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@mpf82 - That's not a duplicate. There's no nesting here. It's just a shallow copy of a `str.split()` operation. – TigerhawkT3 Dec 23 '16 at 10:17
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I interpreted the program and I got output too, But I didn't understand the syntax. @sameerasy – Ravy Dec 23 '16 at 10:20
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1@JitendraReddy I don't understand your comment. You write that you know that it is output, it is not it, is an assigment of a list compression to the variable `items`, it doesn't output anything. – Anthon Dec 23 '16 at 10:20
1 Answers
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It creates a list containing each word from input (from terminal) separated by comma ,.
Edit:
items = [x for x in raw_input().split(',')]
print items
with input from terminal:
this, is, a, string
prints:
['this', ' is', ' a', ' string']
Edit2:
As pointed out in the comments, the list comprehension is redundant, and you would achieve the same using
items = raw_input().split(',')
Edit3:
Also mentioned in the comments, the above approach only works in python version 2. For python3, you'd use
items = input().split(',')
print (items)
Plasma
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See the link to the duplicate question. `raw_input().split(',')` returns a list, `x for x` iterates each element of that list. – Plasma Dec 23 '16 at 10:17
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That will throw a syntax error on the majority of maintained python versions. – Anthon Dec 23 '16 at 10:21
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