In Python 3.5.2, is it possible to remove the decimal place for integers whilst keeping it for floats

Question

If I have a list of both integers and floats and I print it, is there a way to print the integers without a decimal place but keep it for the floats?

I created a game based on the cards in a deck where different cards have different values. The value of each card is then multiplied by either 2, 1.5, 1 or 0.5 based on the suit. This is done randomly. This process is repeated 10 times.

The code looks something like this:

Scores = [2, 4, 6, 8, 10, 12, 15]
Suits = [2, 1.5, 1, 0.5]
TScore = 0
for each in range(10):
Score = random.choice(Scores)
Suit = random.choice(Suits)
TScore = Score * Suit
print("Your score is {0}".format(TScore))

The console may print something like this:

Your score is 12
Your score is 22.5
Your score is 18.0
Your score is 15
Your score is 30
Your score is 6.0
Your score is 6.0
Your score is 6.0
Your score is 12
Your score is 6

Is there a way to make sure that the integers are not followed by a decimal point?

How are you printing them? Are you sure they're not *both* floats? The fact that one could also be an integer can be tested with `float.is_integer`; see e.g. http://stackoverflow.com/q/21583758/3001761 — jonrsharpe, Dec 23 '16 at 19:49
Please provide more details and enough data to enable others to help. — nipy, Dec 23 '16 at 19:54
There is a chance some of your outputs will be of type `int`, while some will be integer values of type `float`, while others will be non-integer rational numbers of type `float`. I suggest you make _all_ the values in `Suits` into `floats` --- regardless of how you intend to display them later --- just to avoid the unexpected fun that mixing kind-of equivalent types can bring you. (Exhibit A: Some of your "integer" outputs have the trailing ".0" while some don't.) — Kevin J. Chase, Dec 24 '16 at 04:21

score 4 · Answer 1 · answered Dec 23 '16 at 19:58

The g or n format type does this for you:

In [560]: for score in [4.0, 22.5]:
     ...:     print('Your score is {:n}'.format(score))
     ...:     
Your score is 4
Your score is 22.5

https://docs.python.org/3/library/string.html#format-specification-mini-language

Shaun Baker · Answer 2 · 2016-12-23T21:43:26.953

1

for score in [4.0, 22.5]:
    '''
    Modulo(%) pulls the remainder, if the number is a whole number
    dividing by 1 should always return 0.
    '''
    if score % 1 == 0:
        score = int(score)
    print(score)

For more information on modulo or other operators: https://www.tutorialspoint.com/python/python_basic_operators.htm

In reference to jonrsharpe's comment above.

    if score.is_integer(): # a float.method returns true if the number is whole.
        score = int(score)
    print(score)

For more information on float.methods: https://docs.python.org/3/library/stdtypes.html#additional-methods-on-float

edited Dec 23 '16 at 21:43

answered Dec 23 '16 at 20:04

Shaun Baker

56
4

if score.is_integer: # a float.method returns true if the number is whole. score = int(score) print(score) it gives 4 if score is 4.0 or 4.8 in both the case – Aman Jaiswal Dec 23 '16 at 20:21
I apologize I entered a syntax error thanks for pointing it out. – Shaun Baker Dec 23 '16 at 20:26

score 0 · Answer 3 · answered Dec 23 '16 at 20:08

I hope it will work in your case:

def removeDecimal(num):
        num1 = list(str(num))
        if(num1[-1]=='0'):      
                return int(num)
        else:
                return num

def main():
        score1 = 4.0
        score2 = 22.5
        print(removeDecimal(score1))    
        print(removeDecimal(score2))
if __name__=="__main__":
        main()

output for this is :

4

22.5

In Python 3.5.2, is it possible to remove the decimal place for integers whilst keeping it for floats

3 Answers3