how to print out an error mesage close to the form field to indicate incorrect outpu in PHP

Question

I have this form element in my php page, and i want to echo out the error message underneath the form element.

     <form method="post" action="<?php $_SERVER['PHP_SELF']; ?>" >
        Name: <input type="text" name="username"><br>
              <span><?php echo nameErr; ?></span>
        password: <input type="password" name="password"><br>
              <span><?php echo passErr; ?></span>
        Gender:<input type="radio" name="gender" value="male">Male
               <input type="radio"  name="gender" value="female">Female
               <span><?php echo genderErr; ?></span>
       </form>

      <?php 
         if($_SERVER['REQUEST_METHOD'] == 'POST')  {
              if(empty($_POST['username'])) {
                  $nameErr = 'name can\'t be empty';
                  else{
                      $username = $_POST['username'];
                  }
               if(empty($_POST['password'])) {
                  $passErr = 'Password can\'t be empty ';
                   else{
                        $password = $_POST['password'];
                  }
               if(empty($_POST['gender'])) {
                      $genderErr = 'Gender cant be empty';
                  }else{
                        $gender = $_POST['gender'];
                  }

       }
         }
      ?>

The major problem is that when i the page is ran, it show error messages that variable $nameErr is not defined, $passErr is not defined, and $genderErr is not defined, My question is that how can i actually notified users of error messages where necessary and it should be close to the form element too.

When the PHP processor run - it goes over your code line-by-line. You print the variable **before** you assign some value to it... — Dekel, Dec 24 '16 at 17:44

score 1 · Accepted Answer · answered Dec 24 '16 at 17:44

1

The way you have given is all wrong. You forgot two things:

$ for the variables.
Since we know this place correctly, we can happily suppress the errors by placing a @ in front.

Change it this way:

<?php echo @$nameErr; ?>
<?php echo @$passErr; ?>
<?php echo @$genderErr; ?>

answered Dec 24 '16 at 17:44

Praveen Kumar Purushothaman

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@pedroyanky *Since we know this place correctly, we can happily **suppress the errors** by placing a `@` in front.* – Praveen Kumar Purushothaman Dec 24 '16 at 17:49
it did worked fine , thanks a lot, just to be sure, the error message will display, when the if statement fail or pass, wouldn't it? – pedroyanky Dec 24 '16 at 17:54
@pedroyanky Check this out: http://php.net/manual/en/language.operators.errorcontrol.php – Praveen Kumar Purushothaman Dec 24 '16 at 17:59
1

@PraveenKumar why suppress errors? Best method here would have been a ternary operator for a few reasons. This is just "my" opinion of course ;-) – Funk Forty Niner Dec 24 '16 at 18:11
@Fred-ii- This situation, even if I use the same format, I'd use `@`. Not being lazy, but seriously, not needed for a right way here. – Praveen Kumar Purushothaman Dec 24 '16 at 18:12
paddy am having this issue , when i left out the password or name field empty, the $passErr; message i echoed out in the span element via the if statement didnt display the message – pedroyanky Dec 24 '16 at 18:33
Sorry, what? I didn't exactly understand. – Praveen Kumar Purushothaman Dec 24 '16 at 18:34

how to print out an error mesage close to the form field to indicate incorrect outpu in PHP

1 Answers1