Python3 regex string formatting

Question

I try get formatting string using python3 regex - re

My input:

{'factorial.2.0.0.zip', 'Microsoft ASP.NET Web API 2.2 Client Libraries 5.2.3.zip', 'Newtonsoft.Json.9.0.1.zip'}

I try get only name and only version for packages, like that:

factorial.2.0.0.zip
- factorial
- 2.0.0
Microsoft ASP.NET Web API 2.2 Client Libraries 5.2.3.zip
- Microsoft ASP.NET Web API 2.2 Client Libraries
- 5.2.3

etc. This my code

if diff is not None:
    for values in diff.values():
        for value in values:
            temp = ''
            temp1 = ''
            temp = re.findall('[aA-zZ]+[0-9]*', value) #name pack
            temp1 = re.findall('\d+', value) #version
            print(temp)
            print(temp1)

My wrong output:

 temp:
 ['Microsoft', 'ASP', 'NET', 'Web', 'API', 'Client', 'Libraries', 'zip']
 ['Newtonsoft', 'Json', 'zip']
 ['factorial', 'zip']

temp1:
['2', '0', '0']
['2', '2', '5', '2', '3']
['9', '0', '1']

Right output:

temp:
['Microsoft', 'ASP', 'NET', 'Web', 'API', 'Client', 'Libraries']
['Newtonsoft', 'Json']
['factorial']

temp1:
['2', '0', '0']
['5', '2', '3']
['9', '0', '1']

how me fix problem, delete "zip" is search and extra numbers. Maybe have another way solved my problem.

I'd strongly recommend to get rid of meaningless identifiers such as temp, whatever you change else. — guidot, Dec 25 '16 at 16:57

score 3 · Accepted Answer · edited May 23 '17 at 11:45

3

Something like this?

import re

a = {'factorial.2.0.0.zip', 'Newtonsoft.Json.9.0.1.zip',\
     'Microsoft ASP.NET Web API 2.2 Client Libraries 5.2.3.zip',\
     'namepack010.0.0.153.212583'}

for b in a:
    c = re.findall('(.*?).(\d+\.\d+\.\d+)(\.zip|\.\d+)$', b)[0]
    if c[2] == '.zip':
        print c[0],'||',c[1]
    else:
        print c[0],'||',c[1]+c[2]

Output:

Newtonsoft.Json || 9.0.1
namepack010 || 0.0.153.212583
Microsoft ASP.NET Web API 2.2 Client Libraries || 5.2.3
factorial || 2.0.0

Don't use [aA-zZ] for selecting all alphabets. It will match some of the special characters also. You should use [a-zA-Z]

Check this for more understanding: Why is this regex allowing a caret?

edited May 23 '17 at 11:45

Community

1
1

answered Dec 25 '16 at 16:56

Mohammad Yusuf

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thanks man, you realy help, but I find name packgs which is not suitable this regex. He looks like this: `namepack010.0.0.153.212583` your regex return `('namepack010.0.0.153.', '12583')` maybe you can help me again? right return this packs: `('namepack010' , '0.0.153.212583')` – teror4uks Dec 25 '16 at 19:38
my solution: `print(re.findall('(.*?\d*\s*)\.*(\d*[^a-zA-Z]*).zip', b)[0])` – teror4uks Dec 25 '16 at 20:29
1

@teror4uks Modified. Check now. – Mohammad Yusuf Dec 26 '16 at 01:53

Python3 regex string formatting

1 Answers1