How to replace the space that follows a digit into comma using python and re package?

Question

How to replace the space that follows a digit into comma using python and re?

For example,

0, 1, 0 12 13 -> 0, 1, 0, 12, 13;

import re

text = "0, 1, 0 12 13"    
matches = re.sub(r'(\d+)\s','*,', text)
print(matches)

but that gives me 0, 1, *, *, *,

You need to replace the `*` with `\1` - see http://stackoverflow.com/questions/14007545/python-regex-instantly-replace-groups/14007559 — Zero Piraeus, Dec 28 '16 at 15:50

score 0 · Answer 1 · answered Dec 28 '16 at 16:06

0

Another way, without re:

text = "0, 1, 0 12 13" 
text = text.replace(',', '') #We remove the commas (to leave them all the same)
text.replace(' ', ', ')      # We replace spaces by comma and space

answered Dec 28 '16 at 16:06

Lucas

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Thanks Ibellomo, but the spaces between these digits are arbitrary. Zero's solution turns out to be very useful. re.sub(r"(\d+)\s", r"\1,", tex). – Shuda Li Dec 28 '16 at 17:48
I do not know `re` and that's why I avoid them. – Lucas Dec 28 '16 at 20:53

How to replace the space that follows a digit into comma using python and re package?

1 Answers1