How to solve this batch glitch?

Question

I have a little problem in my code,
if I

set ghot=1

and

set fo1=text

and try echoing

echo %fo%ghot%%

like this, it comes like

%fo1%

instead of text

FYI people are generally more willing to help if you format your post correctly and write like a grown up. — jonrsharpe, Dec 31 '16 at 12:42
`echo !fo%ghot%!`with Delayed Expansion enabled. The "standard way" to write this _array element_ is `set fo[1]=text` and `echo !fo[%ghot%]!`. See [this post](http://stackoverflow.com/questions/10166386/arrays-linked-lists-and-other-data-structures-in-cmd-exe-batch-script/10167990#10167990) — Aacini, Dec 31 '16 at 16:28

Protium · Answer 1 · 2016-12-31T14:05:11.930

2

I misunderstood what you were asking at first. Adding call to the line will give you the behavior you want.

call echo %%fo%ghot%%%

Edited to add the extra enclosing %'s It works without them from the command line, but not from within a batch file.

edited Dec 31 '16 at 14:05

answered Dec 31 '16 at 13:51

Protium

score 2 · Answer 2 · answered Dec 31 '16 at 16:41

2

An alternative method using delayed expansion:

@Echo Off
SetLocal EnableDelayedExpansion
Set "ghot=1"
Set "fo1=text"
Echo=!fo%ghot%!
Timeout -1

answered Dec 31 '16 at 16:41

Compo

2 Answers2