Switch choosing wrong int case

Question

I have this simple code. An integer which value is 0 and a null String. Simple enough. Yet when I run the program it prints "a" instead of "z". I don't know where's the problem and what am I missing.

public static void main(String[] args) {

    int classCode = 0;
    String classString = null;
    switch(classCode) {
    case 0:
        classString = "z";
    case 10:
        classString = "a";
        break;
    case 11:
        classString = "b";
        break;
    case 20:
        classString = "c";
        break;
    case 21:
        classString = "d";
        break;
    case 30:
        classString = "e ";
        break;
    case 31:
        classString = "f";
        break;
    }
    System.out.println(classString);

}

You're missing a `break;` statement before `case 10:` – 4castle Dec 31 '16 at 19:08 — 4castle, Dec 31 '16 at 19:08

score 2 · Accepted Answer · answered Dec 31 '16 at 19:08

2

You have forgotten to put a break after the first case.

switch(classCode) {
case 0:
    classString = "z";
    // missing a break here
case 10:
    classString = "a";
    break;

answered Dec 31 '16 at 19:08

leeyuiwah

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My bad, I didn't realize that a break was missing :D Thanks a lot! – Virginia Jan 01 '17 at 22:12
You are welcome. We all learn from each other! – leeyuiwah Jan 01 '17 at 22:13

Switch choosing wrong int case

1 Answers1