Ajax request : unexpected identifier

Question

I am solving a challenge where I have to click on a link "http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=12345" get the next nothing number from that page, and insert it at the end of the query string, probably, until there are no more "nothings" left and I have solved it.

I have tried making an Ajax request and getting the data of the next number to use in my next query stting, however oddly I get a syntax error. When I click on the error though, the data I am looking for is shown in the error "and the next nothing is 44827." Here is my code

$(document).ready(function(){
$.getJSON("http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=12345&callback=?",

            function(data){
                console.log(data);
            }
        )
})

How can I do this without getting an error so I can repeatedly get the next "nothing"? And why am I getting a syntax error?

If this is the wrong way to go about solving this, I would appreciate any direction on the correct way to approach this.

Thank.

linkedlist.php?nothing=12345&callback=jQuery3110322…_1483259612759&_=1483259612760:1 Uncaught SyntaxError: Unexpected identifier — n00bi3_stack, Jan 01 '17 at 08:34
Once I hit the link it opens a separate tab in the console and it's just displayed in text : and the next nothing is 44827 — n00bi3_stack, Jan 01 '17 at 08:38
You can work with jsonp - https://learn.jquery.com/ajax/working-with-jsonp/ — Kinnza, Jan 01 '17 at 08:38
Also when you set a callback you need to have an actual function for it to call. So if you add callback=abc, you need a global function abc that handles the callback. the link i posted before shows a better example on how to handle this (jquery will handle it for you) — Kinnza, Jan 01 '17 at 08:40
$.getJSON must receive results in json... if you don't know more about json then you can use simple ajax call ... http://www.w3schools.com/jquery/ajax_ajax.asp — chhameed, Jan 01 '17 at 08:41
@mplungjan tried it with Ajax in that exact form, it returns the same error. First it gives CORS error then I add the dataType:jsonP and it gives same error. — n00bi3_stack, Jan 01 '17 at 08:44
There is no JSON/JSONP support at the URL you give. If there is no CORS support, you need to write a server process - I assume Python challenge means for you to write server side python? http://stackoverflow.com/questions/2667509/curl-alternative-in-python -> http://docs.python-requests.org/en/latest/index.html — mplungjan, Jan 01 '17 at 08:48

score 1 · Answer 1 · edited May 23 '17 at 12:24

1

$.getJSON Load JSON-encoded data from the server using a GET HTTP request.

you can use this code to work without json

 $.ajax({
      method: "GET",
      url: "http://www.pythonchallenge.com/pc/def/linkedlist.php",
      data: { nothing: "12345"}
    })
      .done(function( msg ) {
        console.log(data);
      });

Helping link for CORS support Cross Domain Details

Plugin AJAX Cross Origin!

edited May 23 '17 at 12:24

Community

1
1

answered Jan 01 '17 at 08:48

chhameed

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Assuming it supports CORS – mplungjan Jan 01 '17 at 08:48
And if it doesnt? – n00bi3_stack Jan 01 '17 at 08:51
1

Then you might want to write a server side Python script that gets the next number, parse it and concatenate – mplungjan Jan 01 '17 at 09:00

Ajax request : unexpected identifier

1 Answers1