For loop for an array is not working

Asked Jan 02 '17 at 07:11

Active Jan 02 '17 at 07:17

Viewed 42 times

I want to store all the studentId in one group

i have tried like this:

i am bit new with for/foreach loops.

if($_POST['action']=='startGdstudents')  {
parse_str($_POST['participantsForGd'], $participantsForGd);
$jobID  =   $participantsForGd['jobID'];                      // example: 85
$group  =   mysqli_real_escape_string($conn,$_POST['group']); // example: 2

foreach ($participantsForGd as $k => $v){
    foreach ($v['StudentId'] as $studentid => $student){
    $q = $conn->query("INSERT INTO r_job_groups (student_id,job_id,group_id) VALUES (".$student.",".$jobID.",".$group.") ");
}
}

My errors:

Warning: Illegal string offset 'StudentId' in /home2/amerytec/public_html/lc-latest/gdcontroller .php on line 171

Warning: Invalid argument supplied for foreach() in /home2/amerytec/public_html/lc-latest /gdcontroller.php on line 171

Warning: Invalid argument supplied for foreach() in /home2/amerytec/public_html/lc-latest /gdcontroller.php on line 171

edited Jan 02 '17 at 07:17

jitendrapurohit

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asked Jan 02 '17 at 07:11

Mr world wide

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have you got any errors? – Amruth Jan 02 '17 at 07:14
print `$participantsForGd` and `$v` to debug – Happy Coding Jan 02 '17 at 07:15
is my for loop is correct..? – Mr world wide Jan 02 '17 at 07:25
1

If you say `foreach ($v['StudentId']...` then `$v` must be an array and key `StudentId` must exist. However, `$v` doesn't have a key `StudentId` at all. Try to `print_r()` or `var_dump()` the `$v` variable, and examine the type and value of `$v`. – MC Emperor Jan 02 '17 at 10:02

For loop for an array is not working

0 Answers0