Python variable acting weird

Question

I am making a pattern recogniser and I ran into a VERY strange error. If the pattern is recognised it prints out ["x", "x", "2"] and i set variable worked to t. But when I print out worked on the last line it prints out ["x", "x", "x"]

(See the part of code marked # _____________ IMPORTANT __________ #)

    import random

    def check_pattern(pattern, rule):
        for i, RULE in enumerate(pattern):
            if RULE != "x":
                if rule[i] != RULE:
                    return False
        return True

    if __name__ == "__main__":
        numbers = [002,212,212,432,132,142,322,992,972,692,942,472]

        #numbers = [a.replace("\n", "") for a in numbers]

        print("Finding pattern in {}".format(numbers))

        patterns = []
        possible = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "x"]

        found = False
        pattern = ["x", "x", "x"]
        working = []
        worked = []
        for i, rule in enumerate(pattern):
            for attemptRule in possible:
                testRule = pattern
                testRule[i] = str(attemptRule)
                works = True

                for num in numbers:
                    numList = [a for a in str(num)]
                    if check_pattern(testRule, numList):
                        pass
                        #print("Pattern {} works with {}".format(t, numList))
                    else:
                        works = False
                        #print("Pattern {} doesnt work with {}".format(t, numList))
                if works:
                    # ____________________ IMPORTANT ______________________ #
                    if testRule != ['x', 'x', 'x']:
                        print(testRule)                    
                        worked = testRule
                    # ____________________ IMPORTANT ______________________ #
                    working.append(testRule)
        #print("Pattern {} works".format(working))
    print(worked)

Thanks.

In line 31: numList = [a for a in num] TypeError: 'int' object is not iterable — Emanuele Paolini, Jan 02 '17 at 09:24
I now call str() on the numbers and change 1 to "1" and so on. Updating post, thanks for reply but i dont get any errors — jotjern, Jan 02 '17 at 09:29
I find it hard to read the code, what is it supposed to do? Can you give some examples of input and expected output? — fafl, Jan 02 '17 at 09:32
Uhhhh i think i already have expected input and output but ill make it more clear... — jotjern, Jan 02 '17 at 09:33
I don't really try to understand your code but `testRule = pattern` is probably the problem, see http://stackoverflow.com/questions/2612802/how-to-clone-or-copy-a-list — polku, Jan 02 '17 at 09:33
right now you have a SyntaxError on number `002` (line 11). To fix it, remove the 2 leading 0 then replace `str(num)` by `"%3d" % num` line 31. — Guillaume, Jan 02 '17 at 09:37

jotjern · Answer 1 · 2017-01-02T12:50:29.960

0

I found my answear. The problem was that i didn't clone the list and overwrote it instead. Thanks to polku i understood. Thanks everyone.

edited Jan 02 '17 at 12:50

answered Jan 02 '17 at 09:36

jotjern

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Python variable acting weird

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