How do you put the last character 1st in a string

Question

The R is displaying last in the string initially it must display first how can I put the last character before the number value in the string so that it can display at the beginning of the value

contentHtml += 
    "<td rowspan1=\"" + 1 + "\" class=\"" + (rowspan !== "" && rowspan > 1 ? "groups" : "") + " " + (!isNaN(value) || (!isNaN(value.toString().substr(1, value.length)) || value == "N/A" || value.length < 7 && value.toString().substr(value.length - 1) == '%') ? "text-center" : "text-left") + "\">" + value + (!isNaN(value) ? preFix : "") + color + (!isNaN(value) ? postFix : "") + "</td>";
if (rowspan > 1) {
    var rowspanContent = "<td rowspa1=\"" + rowspan + "\" class=\"" + (rowspan !== "" && rowspan > 1 ? "groups" : "") + " " + (!isNaN(value) || (!isNaN(value.toString().substr(1, value.length)) || value == "N/A" || value.length < 7 && value.toString().substr(value.length - 1) == '%') ? "text-center" : "text-left") + "\">" + value + (!isNaN(value) ? preFix : "") + color + (!isNaN(value) ? postFix : "") + "</td>";
}

Please use the search function in future: http://stackoverflow.com/questions/5306680/move-an-array-element-from-one-array-position-to-another — RushRed, Jan 03 '17 at 12:07

Cruz · Answer 1 · 2017-01-03T13:40:31.847

2

If you want o swap the numbers and letters you should see Nina Scholz answer.

If you just want to put the last character first you can do it like this:

function lastToFirst(value){
   return value.slice(-1) + value.substring(0,value.length-1);
}

or even cleaner

function lastToFirst(value){
   return value.slice(-1) + value.slice(0,-1);
}

edited Jan 03 '17 at 13:40

answered Jan 03 '17 at 12:11

Cruz

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1

you could use `slice` for the number part as well: `return value.slice(-1) + value.slice(0, -1);` – Nina Scholz Jan 03 '17 at 12:15
Yup, you are right, that's even better! – Cruz Jan 03 '17 at 13:17

Nina Scholz · Accepted Answer · 2017-01-03T12:22:23.093

1

You could use a regular expression and swap numbers and letters (not numbers).

function swap(s) {
    var m = s.match(/^(\d+)(\D+)$/);
    return m[2] + m[1];
}

console.log(swap('1234R'));

Otherwise, you could change your code from

value + (!isNaN(value) ? preFix : "") + color + (!isNaN(value) ? postFix : "")
//      ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

to

(!isNaN(value) ? preFix : "") + value + color + (!isNaN(value) ? postFix : "")
//^^^^^^^^^^^^^^^^^^^^^^^^^^^

and use preFix instead of postFix.

edited Jan 03 '17 at 12:22

answered Jan 03 '17 at 12:06

Nina Scholz

376,160
25
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Thanx this is the correct answer + "" + (!isNaN(value) ? preFix : "") + value + (!isNaN(value) ? postFix : "") + color + – Graeme Richard Petersen Jan 03 '17 at 19:30

Banzay · Answer 3 · 2017-01-04T07:37:38.733

1

Direct answer is:

var value ="1234567R";
var res = "R" + value.split("R")[0];
alert(res);

edited Jan 04 '17 at 07:37

answered Jan 03 '17 at 12:23

Banzay

9,310
2
27
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Zakawa · Answer 4 · 2017-01-03T12:18:11.973

0

Without code, it's compicated to help. If just you want to put the last x chars to first, here is a little piece of code

var nb = 1;
var s = "123456789R";
var last = s.split(s[s.length - (nb - 1)])[1];
var s1 = s.slice(0, s.length - nb);
s = last + s1;
//s => "R123456789"

edited Jan 03 '17 at 12:18

answered Jan 03 '17 at 12:11

Zakawa

132
1
5

How do you put the last character 1st in a string

4 Answers4