This looks like a short circuit way of writing code but I just can't understand it. Is there a specific way to read this kind of short circuit.
e.g:
n = n and int(n)
n = n or int(n)
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@vaultah - This is a not operator question. I meant to understand short circuit version here. – user1113186 Jan 05 '17 at 16:24
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Answers on that page explain the behaviour of the `and` operator perfectly, you just need to apply them to your code. – vaultah Jan 05 '17 at 16:31
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that's correct but I dont understand how n and int(n)..is working here. How this expression is being evaluated? – user1113186 Jan 05 '17 at 17:09
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According to [this](http://stackoverflow.com/a/19187401/2301450) answer, `x and y` means *"if x is false, then x, else y"*. Substitute *x* for `n` and *y* for `int(n)`. – vaultah Jan 05 '17 at 17:12
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Thanks I got it now. – user1113186 Jan 05 '17 at 18:42
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and conditions return the last truthy value or the first falsy one. So if n is falsy, n will remain whatever value it was. If n is truthy, it will be cast to an int.
mVChr
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this makes sense. so n = n or int(n) would mean that whatever n would evaluate to ( if n is true or false), next expression int(n) won't be evaluated (it would be skipped)? – user1113186 Jan 05 '17 at 17:12