PHP Replace src link and keep url

Question

I have a source code like this:

<script type='text/javascript' src='http://html.com/wp-content/plugins/contact-form-7/includes/js/scripts.js?ver=4.6'></script>
<script type='text/javascript'></script>
<script type='text/javascript' src='http://html.com/wp-content/plugins/table-of-contents-plus/front.min.js?ver=1509'></script>
<script type='text/javascript' src='http://html.com/wp-includes/js/wp-embed.min.js?ver=4.7'></script>

How can I replace ALL the src attributes with:

"http://www.example.com/site=PLACEHOLDER&somethingelse"? So I need to replace PLACEHOLDER with {the src website from above}

I found code snippets where I could replace the src link but not replacing it with a replaced url of itself.

How would one do that?

You could pull all `script` elements, then pull the `src` attribute from it, then replace it or modify it as needed. — chris85, Jan 06 '17 at 15:53
Possible duplicate of [How do you parse and process HTML/XML in PHP?](http://stackoverflow.com/questions/3577641/how-do-you-parse-and-process-html-xml-in-php) — chris85, Jan 06 '17 at 15:53

score 1 · Accepted Answer · answered Jan 06 '17 at 16:13

Assuming you have the source code inside a variable you can do:

$code = "
<script type='text/javascript' src='http://html.com/wp-content/plugins/contact-form-7/includes/js/scripts.js?ver=4.6'></script>
<script type='text/javascript'></script>
<script type='text/javascript' src='http://html.com/wp-content/plugins/table-of-contents-plus/front.min.js?ver=1509'></script>
<script type='text/javascript' src='http://html.com/wp-includes/js/wp-embed.min.js?ver=4.7'></script>";

$pattern = "/src='([^']+)/i";
$replacement = "src='http://www.example.com/site=$1&somethingelse";

echo preg_replace($pattern, $replacement, $code);

This looks like a perfect solution! Thank you very much! – user754730 Jan 09 '17 at 09:27 — user754730, Jan 09 '17 at 09:27

PHP Replace src link and keep url

1 Answers1