C# get uri arguments

Question

http://localhost/ReportServer/Reserved.ReportServer?/Report+Project1&rs:Command=ListChildren

I would like get parts of url with report folder (Report Project1). I tried HttpContext.Current.Request.Url.Segments but this return array with this items: "\", "ReportServer", "Reserved.ReportServer"

How I get parts with Report Project1?

This are query string paramaters ... Try this `HttpContext.Current.Request.QueryString` — Martin E, Jan 09 '17 at 12:11
Thanks, but in QueryString is array AllKeys which contains 2 items: null and rs:Command, Report Project 1 isnt in this array — bluray, Jan 09 '17 at 12:17
than you Need to build your url correctly which would be: ...ReportServer?/&Report=Project1&rs=ListChildren or what is rs supposed to be. than Access it via ctx.Request.Params.Get("rs") or ("Report") or via QueryString — Luca, Jan 09 '17 at 12:18
Or try removing the `/` after your `?`. this could be the problem. — Martin E, Jan 09 '17 at 12:24

score 2 · Accepted Answer · answered Jan 09 '17 at 12:24

2

This is correct solution:

HttpContext.Current.Request.QueryString.Get(0)

answered Jan 09 '17 at 12:24

bluray

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but be aware that the parameter has to be on first place ever – Martin E Jan 09 '17 at 12:25
Yes, this url is in Reporting Server, it will not change – bluray Jan 09 '17 at 12:28
well then that fits :) – Martin E Jan 09 '17 at 12:32

score 1 · Answer 2 · answered Jan 09 '17 at 12:39

Because the query in this request aren't standard i.e. the first parameter doesn't have a variable name only the folder path, you can't get the URI query param in a reliable way. The following code will provide the functionality you want, but perhaps using a simple String.split() looking for the regex of folder would be more reliable.

Uri temp = new Uri("http://localhost/ReportServer/Reserved.ReportServer?/Report+Project1&rs:Command=ListChildren");
string query = temp.Query;
var folder = HttpUtility.ParseQueryString(query).Get(null);

Where the null value is in the Get method, you should really provide the variable name, in your example putting rs:Command there would return the value of that param.

C# get uri arguments

2 Answers2